41.8 because u just move one over
The equation of the line that cuts through (0,5) and (1,2) is y = -3x + 5
<h3><u>Solution:</u></h3>
Given that we have to find equation of the line that cuts through (0,5) and (1,2)
The equation of line passing through points
and
is given as:

Where "m" is the slope of line
Let us first find slope of line
<em><u>The slope of line is given as:</u></em>



<em><u>Thus the required equation of line is:</u></em>

Thus the equation of line is found
Answer:

Step-by-step explanation:
We can write
as follows:
![\frac{11s}{s^2-12s+52}\\=11\left [ \frac{s}{s^2-12s+52} \right ]\\=11\left [ \frac{s}{(s-6)^2+16} \right ]\\=11\left [ \frac{s-6+6}{(s-6)^2+16} \right ]\\=11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16}](https://tex.z-dn.net/?f=%5Cfrac%7B11s%7D%7Bs%5E2-12s%2B52%7D%5C%5C%3D11%5Cleft%20%5B%20%5Cfrac%7Bs%7D%7Bs%5E2-12s%2B52%7D%20%5Cright%20%5D%5C%5C%3D11%5Cleft%20%5B%20%5Cfrac%7Bs%7D%7B%28s-6%29%5E2%2B16%7D%20%5Cright%20%5D%5C%5C%3D11%5Cleft%20%5B%20%5Cfrac%7Bs-6%2B6%7D%7B%28s-6%29%5E2%2B16%7D%20%5Cright%20%5D%5C%5C%3D11%5Cleft%20%5B%20%5Cfrac%7Bs-6%7D%7B%28s-6%29%5E2%2B16%7D%20%5Cright%20%5D%2B%5Cfrac%7B66%7D%7B%28s-6%29%5E2%2B16%7D)
To find:
![L^{-1}\left [ \frac{11s}{s^2-12s+52 \right ]}\\=L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16} \right ]](https://tex.z-dn.net/?f=L%5E%7B-1%7D%5Cleft%20%5B%20%5Cfrac%7B11s%7D%7Bs%5E2-12s%2B52%20%5Cright%20%5D%7D%5C%5C%3DL%5E%7B-1%7D%5Cleft%20%5B%2011%5Cleft%20%5B%20%5Cfrac%7Bs-6%7D%7B%28s-6%29%5E2%2B16%7D%20%5Cright%20%5D%2B%5Cfrac%7B66%7D%7B%28s-6%29%5E2%2B16%7D%20%5Cright%20%5D)
We will use formulae:

we get solution as :
![L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16} \right ]\\=L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+4^2} \right ]+\frac{66}{4}\left [ \frac{4}{(s-6)^2+4^2} \right ] \right ]\\=11e^{6t}\cos 4t+\frac{33}{2}e^{6t}\sin 4t](https://tex.z-dn.net/?f=L%5E%7B-1%7D%5Cleft%20%5B%2011%5Cleft%20%5B%20%5Cfrac%7Bs-6%7D%7B%28s-6%29%5E2%2B16%7D%20%5Cright%20%5D%2B%5Cfrac%7B66%7D%7B%28s-6%29%5E2%2B16%7D%20%5Cright%20%5D%5C%5C%3DL%5E%7B-1%7D%5Cleft%20%5B%2011%5Cleft%20%5B%20%5Cfrac%7Bs-6%7D%7B%28s-6%29%5E2%2B4%5E2%7D%20%5Cright%20%5D%2B%5Cfrac%7B66%7D%7B4%7D%5Cleft%20%5B%20%5Cfrac%7B4%7D%7B%28s-6%29%5E2%2B4%5E2%7D%20%5Cright%20%5D%20%5Cright%20%5D%5C%5C%3D11e%5E%7B6t%7D%5Ccos%204t%2B%5Cfrac%7B33%7D%7B2%7De%5E%7B6t%7D%5Csin%204t)
Answer:
The number of car washed per club is:
The art club = 533 cars
The music club = 633 cars
The drama club = 414 cars
Step-by-step explanation:
The art club, music club, and drama club at Glendale High School raised money last summer by washing cars.•
For the art club
The art club raised about $3,200 and charged $6 per car.•
$6 = 1 car
$3200 = x
6x = 3200
x = 3200/6
x = 533.33333333 cars
Approximately = 533 cars
The music club earned approximately $3,800, charging $8 for each car
$8 = 1 car
$3800 = x
8x = 3800
x = 3800/8
x = 633.33333333 cars
Approximately = 633 cars
The drama club took in nearly $2,900, at a cost per car of $7.
$7= 1 car
$2900 = x
7x = 2900
x = 2900/7
x = 414.28571429 cars
Approximately = 414 cars
The number of car washed per club is:
The art club = 533 cars
The music club = 633 cars
The drama club = 414 cars
THE ANSWER IS 11 100% RIGHT