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exis [7]
3 years ago
12

How does a bee part his hair? (This is not a joke,to not take take this down please)

Mathematics
2 answers:
Lina20 [59]3 years ago
8 0

Answer:

Using a honey comb

Step-by-step explanation:

A bee would part his hair using a honey comb.

igomit [66]3 years ago
7 0
With his honey comb
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Alan purchased 16 shares of company stock for $390.40. A month later, the total value of his shares fell to $291.20. What is the
sp2606 [1]
291.20 / 16 = 18.20 per share
7 0
3 years ago
4 A game is being watched by 60 adults and some
Vladimir79 [104]

Answer:

20 children.

Step-by-step explanation:

We can solve this using an equation or simple mental math:

The equation: x=children x+20=adults

x + (x+20) = 60

2x + 20 = 60

2x = 40

x = 20

Mental Math: 40 plus 20 is 60 and 40 is 20 more than 20 so there are 40 adults and 20 children.

5 0
2 years ago
Refer To The Equation 2x-6y=12<br> Please Help :)
Juli2301 [7.4K]

I'm sorry I can't answer that but I know something so you can answer that. search in browser 'quickmath' all your problems, equations and more can be solved

Step-by-step explanation:

I hope it helps trust me

8 0
3 years ago
Find the point P on the graph of the function y=√x closest to the point (9,0)
Sphinxa [80]

Answer:

\displaystyle \frac{17}{2}.

Step-by-step explanation:

Let the x-coordinate of P be t. For P\! to be on the graph of the function y = \sqrt{x}, the y-coordinate of \! P would need to be \sqrt{t}. Therefore, the coordinate of P \! would be \left(t,\, \sqrt{t}\right).

The Euclidean Distance between \left(t,\, \sqrt{t}\right) and (9,\, 0) is:

\begin{aligned} & d\left(\left(t,\, \sqrt{t}\right),\, (9,\, 0)\right) \\ &= \sqrt{(t - 9)^2 +\left(\sqrt{t}\right)^{2}} \\ &= \sqrt{t^2 - 18\, t + 81 + t} \\ &= \sqrt{t^2 - 17 \, t + 81}\end{aligned}.

The goal is to find the a t that minimizes this distance. However, \sqrt{t^2 - 17 \, t + 81} is non-negative for all real t\!. Hence, the \! t that minimizes the square of this expression, \left(t^2 - 17 \, t + 81\right), would also minimize \sqrt{t^2 - 17 \, t + 81}\!.

Differentiate \left(t^2 - 17 \, t + 81\right) with respect to t:

\displaystyle \frac{d}{dt}\left[t^2 - 17 \, t + 81\right] = 2\, t - 17.

\displaystyle \frac{d^{2}}{dt^{2}}\left[t^2 - 17 \, t + 81\right] = 2.

Set the first derivative, (2\, t - 17), to 0 and solve for t:

2\, t - 17 = 0.

\displaystyle t = \frac{17}{2}.

Notice that the second derivative is greater than 0 for this t. Hence, \displaystyle t = \frac{17}{2} would indeed minimize \left(t^2 - 17 \, t + 81\right). This t\! value would also minimize \sqrt{t^2 - 17 \, t + 81}\!, the distance between P \left(t,\, \sqrt{t}\right) and (9,\, 0).

Therefore, the point P would be closest to (9,\, 0) when the x-coordinate of P\! is \displaystyle \frac{17}{2}.

8 0
3 years ago
NOT THE SAME 1 FROM BEFORE
masha68 [24]

Answer:

B. 40 ≤ e ≤ 100

Step-by-step explanation:

In a function, the domain values are the independent variables, and are always plotted on the x-axis, while the range values the dependent variables, which are always plotted on the y-axis on a graph.

From the graph given, it shows that f is a function of e. Which is, e(f).

Therefore, the range of the function would be: B. 40 ≤ e ≤ 100

3 0
3 years ago
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