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3 years ago

How does a bee part his hair? (This is not a joke,to not take take this down please)

Mathematics

2 answers:

Lina20 [59]3 years ago

8 0

Answer:

Using a honey comb

Step-by-step explanation:

A bee would part his hair using a honey comb.

igomit [66]3 years ago

7 0

With his honey comb

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Alan purchased 16 shares of company stock for $390.40. A month later, the total value of his shares fell to $291.20. What is the

sp2606 [1]

291.20 / 16 = 18.20 per share

7 0

3 years ago

4 A game is being watched by 60 adults and some

Vladimir79 [104]

Answer:

20 children.

Step-by-step explanation:

We can solve this using an equation or simple mental math:

The equation: x=children x+20=adults

x + (x+20) = 60

2x + 20 = 60

2x = 40

x = 20

Mental Math: 40 plus 20 is 60 and 40 is 20 more than 20 so there are 40 adults and 20 children.

5 0

2 years ago

Refer To The Equation 2x-6y=12<br> Please Help :)

Juli2301 [7.4K]

I'm sorry I can't answer that but I know something so you can answer that. search in browser 'quickmath' all your problems, equations and more can be solved

Step-by-step explanation:

I hope it helps trust me

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3 years ago

Find the point P on the graph of the function y=√x closest to the point (9,0)

Sphinxa [80]

Answer:

$\displaystyle \frac{17}{2}$ .

Step-by-step explanation:

Let the $x$ -coordinate of $P$ be $t$ . For $P\!$ to be on the graph of the function $y = \sqrt{x}$ , the $y$ -coordinate of $\! P$ would need to be $\sqrt{t}$ . Therefore, the coordinate of $P \!$ would be $\left(t,\, \sqrt{t}\right)$ .

The Euclidean Distance between $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ is:

$\begin{aligned} & d\left(\left(t,\, \sqrt{t}\right),\, (9,\, 0)\right) \\ &= \sqrt{(t - 9)^2 +\left(\sqrt{t}\right)^{2}} \\ &= \sqrt{t^2 - 18\, t + 81 + t} \\ &= \sqrt{t^2 - 17 \, t + 81}\end{aligned}$ .

The goal is to find the a $t$ that minimizes this distance. However, $\sqrt{t^2 - 17 \, t + 81}$ is non-negative for all real $t\!$ . Hence, the $\! t$ that minimizes the square of this expression, $\left(t^2 - 17 \, t + 81\right)$ , would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ .

Differentiate $\left(t^2 - 17 \, t + 81\right)$ with respect to $t$ :

$\displaystyle \frac{d}{dt}\left[t^2 - 17 \, t + 81\right] = 2\, t - 17$ .

$\displaystyle \frac{d^{2}}{dt^{2}}\left[t^2 - 17 \, t + 81\right] = 2$ .

Set the first derivative, $(2\, t - 17)$ , to $0$ and solve for $t$ :

$2\, t - 17 = 0$ .

$\displaystyle t = \frac{17}{2}$ .

Notice that the second derivative is greater than $0$ for this $t$ . Hence, $\displaystyle t = \frac{17}{2}$ would indeed minimize $\left(t^2 - 17 \, t + 81\right)$ . This $t\!$ value would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ , the distance between $P$ $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ .

Therefore, the point $P$ would be closest to $(9,\, 0)$ when the $x$ -coordinate of $P\!$ is $\displaystyle \frac{17}{2}$ .

8 0

3 years ago

NOT THE SAME 1 FROM BEFORE

masha68 [24]

Answer:

B. 40 ≤ e ≤ 100

Step-by-step explanation:

In a function, the domain values are the independent variables, and are always plotted on the x-axis, while the range values the dependent variables, which are always plotted on the y-axis on a graph.

From the graph given, it shows that f is a function of e. Which is, $e(f)$ .

Therefore, the range of the function would be: B. 40 ≤ e ≤ 100

3 0

3 years ago