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Marrrta [24]
3 years ago
12

Is anyone else Edge not working?

Mathematics
2 answers:
swat323 years ago
6 0

Answer: what do you mean by edge?

Step-by-step explanation: Please clarify and provide more information please.

ollegr [7]3 years ago
3 0

Answer:

No, mine isn't really working.

Step-by-step explanation:

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Do u agree or disagree and why?
pshichka [43]

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Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer
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Answer:

C) Both

Step-by-step explanation:

The given equation is:

0=(3x+2)(x-4)

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply (3x+2)(x-4) i.e. 3x^2-12x+2x-8 = 3x^2-10x-8

So, the equation becomes:

0=3x^2-10x-8

Comparing this equation to standard quadratic equation:

ax^2+bx+c=0

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}

The answer is same from both the approaches.

So, the correct answer is:

C) Both

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All vertical and horizontal cross sections of any one cube are all the same size and shape. What about vertical and horizontal c
svetlana [45]
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Horizontal cross sections are different size: the more we go to the top of the pyramind, the smaller they get.
Vertical cross sections are different size: the closer we get to the edges, the smaller they become.
8 0
3 years ago
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