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3 years ago

Is anyone else Edge not working?

Mathematics

2 answers:

swat323 years ago

6 0

Answer: what do you mean by edge?

Step-by-step explanation: Please clarify and provide more information please.

ollegr [7]3 years ago

3 0

Answer:

No, mine isn't really working.

Step-by-step explanation:

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Pleaseeee help meeeee What is ∑n=125(3n−2) equal to?

vichka [17]

Answer:

$\sum_{n=1}^{25}(3n-2)=925]$

Step-by-step explanation:

The given series is $\sum_{n=1}^{25}(3n-2)$

The first term of this series is

$a_1=3(1)-2$

$a_1=3-2$

$a_1=1$

The second term is

$a_2=3(2)-2$

$a_2=6-2$

$a_2=4$

The common difference is

$d=4-1=3$

The sum of the first n-terms is given by;

$S_n=\frac{n}{2}[2a_1+d(n-1)]$

The sum of the first 25 terms of the series is

$S_{25}=\frac{25}{2}[2(1)+3(25-1)]$

$S_{25}=\frac{25}{2}[2+3(24)]$

$S_{25}=\frac{25}{2}(74)]$

$S_{25}=925]$

4 0

4 years ago

Read 2 more answers

(-2x + 4) + 2(2x + 1)

Wittaler [7]

-2x+4+4x+2=2x+6
Answer:2x+6
Hope this is what you were looking for

5 0

3 years ago

Rewrite the quadratic function below in Standard Form. y = (x - 4) (x + 3)

Damm [24]

the standard form of a quadratic formula is

y = ax^2 + bx + c

in this case you will solve using foil method

(× - 4)(x + 3)

(x × x) +( x × 3 )(- 4 × x) ( -4)× 3))

x^2 + 3x - 4x -12

x^2 - x - 12

therefore

y = x^2- x - 12

5 0

3 years ago

Find the derivative g(t)=7t4 –4t3 +6t2 +9t–19

Fiesta28 [93]

Answer:

28t³ - 12t² + 12t + 1

Step-by-step explanation:

Derivative Rule

xⁿ = nxⁿ⁻¹

Solving

g(t) = 7t⁴ - 4t³ + 6t² + 9t - 19
g'(t) = 4(7t)⁴⁻¹ - 3(4t)³⁻¹ + 2(6t)²⁻¹ + 1(9t)¹⁻¹ - 0
g'(t) = 28t³ - 12t² + 12t + 1

6 0

3 years ago

PROBLEM: (IF YOU TROLL I WILL REPORT) Riley has a rectangular shaped patio that is 13 feet long by 15 feet wide. He wants to DOU

rusak2 [61]

Answer:

Part A)

$390=(15+x)(13+x)$

Part B)

Approximately 18.77 feet long by 20.77 feet wide.

Step-by-step explanation:

Currently, the patio is 13 feet long by 15 feet wide. Therefore, the area right now is:

$A=13(15)=195\text{ feet}^2$

We will increase the length and width of the patio by the same amount such that the new area is double the previous amount.

Part 1)

The previous area is 195. Therefore, we would like to the new area to be twice of that. Hence, the new area is:

$A=2(195)=390$

We will increase the length and the width by the same amount. Let’s call this amount x. Then by the area formula (A=bh), we can write:

$390=(15+x)(13+x)$

390 represents the doubled area. (15+x) is the width after the increase x, and (13+x) is the length after the same x increment.

Part 2)

So, we will solve for x. First, expand:

$390=195+15x+13x+x^2$

Simplify:

$x^2+28x+195=390$

Subtract 390 from both sides:

$x^2+28x-195=0$

This is a quadratic. Hence, we can use the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Our a=1, b=28, and c=-195. Hence:

$x=\frac{-28\pm\sqrt{(28)^2-4(1)(-195)}}{2(1)}$

Evaluate:

$x=\frac{-28\pm\sqrt{1564}}{2}$

Simplify the square root:

$\sqrt{1564}=\sqrt{4}\cdot\sqrt{391}=2\sqrt{391}$

Hence:

$x=\frac{-28\pm2\sqrt{391}}{2}\\$

Simplify:

$x=-14+\sqrt{391} \text{ or } -14-\sqrt{391}$

Approximate:

$x\approx5.77\text{ or } x\approx-33.77$

In this case, we can reject the negative solution.

Hence, the value of x is 5.77.

This means that we should increase the our length and width by 5.77.

Hence, the new length will be 13+5.77 or about 18.77.

And our new width will be 15+5.77 or about 20.77.

So, the new dimensions is approximately 18.77 by 20.77

5 0

3 years ago