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Serga [27]
2 years ago
11

The high for yesterday was 90°F, today the high is 78°F. What is the percent decrease in the

Mathematics
1 answer:
Sati [7]2 years ago
6 0

Answer:

The temperature from yesterday to today decreased by 12 degrees fahrenheit.

Step-by-step explanation:

Ummm... it's true :)

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What's -5.25 as a whole number
koban [17]
That is technically impossible but I can put this into a mixed fraction which is -5 1/4
4 0
3 years ago
Suppose you work for a large coffee distribution that has a secret coffee blend it sells to local stores. Gazebo blend with Kona
KATRIN_1 [288]

Answer:

12 Pounds

Step-by-step explanation:

The proportion of the secret blend is 90/27. When there is only 40 pounds of gazebo, your proportion looks like this:  40/X. X being pounds of Kona. When you are to simplify 90/27 you're left with 10/3. Cross multiply 10/3 and 40/X to and simply to get 10x = 120, leaving you with 12 as your final answer. Hope this explanation helps.

8 0
3 years ago
Select "Growth" or "Decay" to classify each function.
allochka39001 [22]

1. The growth rate equation has a general form of:

y = A (r)^t

The function is growth when r≥1, and it is a decay when r<1. Therefore:

y=200(0.5)^2t                    --> Decay

y=1/2(2.5)^t/6                  --> Growth

y=(0.65)^t/4                       --> Decay

 

2. We rewrite the given equation (1/3)^d−5 = 81

 

Take the log of both sides:

(d – 5) log(1/3) = log 81

d – 5 = log 81 / log(1/3)

d – 5 = - 4

 

Multiply both sides by negative 1:

- d + 5 = 4

So the answer is D

5 0
3 years ago
Pls help with 19 tysm its also worth branliest ty if u help
Mariana [72]
I’ll help you out, but what are the numbers in between? Like does it go boy 0, .3, .6, .9, to 1? Or is there a different pattern
5 0
3 years ago
Read 2 more answers
Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF
drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD    and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

\therefore m\angle A = m\angle B ⇒1

And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

m\angle F=m\angle E=90\° ⇒2

Now In △ABE and △CBF

∠A = ∠C   (from 1)

∠E = ∠F    (from 2)

So by A.A. similarity postulate;

△ABE∼△CBF

7 0
3 years ago
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