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love history [14]
3 years ago
14

Consider this system of equations. Which equation represents the first equation written in slope-intercept form? 5 x minus 2 y =

10. Y = one-fourth x + 1.
Mathematics
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

y = \frac{5x}{2} - 5

Step-by-step explanation:

Given the equation 5x - 2y = 10, to write the equation in slope-intercept form, we need to write it in the standard format y = mx+c where m is the slope/gradient and c is the intercept.

From the equation given  5x - 2y = 10, we will make y the subject of the formula as shown;

5x - 2y = 10\\\\subtract \ 5x \ from \ both \ sides\\\\5x - 2y - 5x = 10 - 5x\\\\-2y = 10-5x\\\\Dividing \ both \ sides\ by  \ -2;\\\\\frac{-2y}{-2} = \frac{10-5x}{-2}\\  \\

y = \frac{10}{-2} - \frac{5x}{-2}  \\\\y = -5 + \frac{5x}{2}\\\\y = \frac{5x}{2} - 5

Hence the equation that represents the first equation written in slope-intercept form is y = \frac{5x}{2} - 5

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