Consider this system of equations. Which equation represents the first equation written in slope-intercept form? 5 x minus 2 y =
1 answer:
Answer:
Step-by-step explanation:
Given the equation 5x - 2y = 10, to write the equation in slope-intercept form, we need to write it in the standard format y = mx+c where m is the slope/gradient and c is the intercept.
From the equation given 5x - 2y = 10, we will make y the subject of the formula as shown;
Hence the equation that represents the first equation written in slope-intercept form is
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Explanation:
Vertex form of a quadratic function is given by y = a(x - h)² + k
where
1) 'a' determines if parabola is stretched or compressed.
If a > 1 then graph is stretched by a factor of a.
If 0 < a < 1, then graph is compressed by a factor of a.
2) If a > 0 then graph opens upwards with a happy face. (minimum)
3) If a < 0 then graph opens downwards with a sad face. (maximum)
4) (h, k) is the vertex point
5) The axis of symmetry is x = h
While solving for y = 1(x - 4)² + 3
Identify following's:
Vertex: (h, k) = (4, 3)
Axis of symmetry: x = 4
Max/Min: As here a > 0, Minimum (4, 3)
Stretch/compression: a = 1, the graph is stretched by a factor of 1.
Direction of opening: As a > 0, the graph opens upwards.
Answer:
look at the screenshot hun!!
Step-by-step explanation:
