Question

Consider this system of equations. Which equation represents the first equation written in slope-intercept form? 5 x minus 2 y = 10. Y = one-fourth x + 1.

Answer 1

Answer:

$y = \frac{5x}{2} - 5$

Step-by-step explanation:

Given the equation 5x - 2y = 10, to write the equation in slope-intercept form, we need to write it in the standard format y = mx+c where m is the slope/gradient and c is the intercept.

From the equation given  5x - 2y = 10, we will make y the subject of the formula as shown;

$5x - 2y = 10\\\\subtract \ 5x \ from \ both \ sides\\\\5x - 2y - 5x = 10 - 5x\\\\-2y = 10-5x\\\\Dividing \ both \ sides\ by \ -2;\\\\\frac{-2y}{-2} = \frac{10-5x}{-2}$

$y = \frac{10}{-2} - \frac{5x}{-2} \\\\y = -5 + \frac{5x}{2}\\\\y = \frac{5x}{2} - 5$

Hence the equation that represents the first equation written in slope-intercept form is $y = \frac{5x}{2} - 5$