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abruzzese [7]
2 years ago
13

Rearrange equation iterative

Mathematics
1 answer:
faltersainse [42]2 years ago
4 0
Numerical methods; Rearrange your equation; Find the negative root of fact equation. Then you have your answer.
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a group of 4 pupils can take 2 weeks to do a certain job.how long will 12 pupils take to complete the job if they work at the sa
Ksivusya [100]

Answer:

6 weeks

Step-by-step explanation:

Set up a proportion where x is the amount of time with 12 pupils:

\frac{4}{2} = \frac{12}{x}

Cross multiply and solve for x:

4x = 24

x = 6

So, it will take 12 pupils 6 weeks to complete the job.

7 0
2 years ago
Need help please i don't know how to do this one
kakasveta [241]
I believe it’s 14.97
3 0
3 years ago
Tiffany is planning a vacation. The hotel costs $60 per night and her flight costs $220. Tiffany has $600 dollars to spend on th
Masteriza [31]

Answer:

60n+220=600

Step-by-step explanation:

6 0
3 years ago
The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
3 years ago
Big Time Movers charges an initial fee of $24.50, plus $12.75 an hour for their moving services. On holidays, they charge 2.5 ti
stiv31 [10]
2.5(12.75x + 24.50) = 188.75
31.875x + 61.25 = 188.75
31.875x = 188.75 - 61.25
31.875x = 127.50
x = 127.50 / 31.875
x = 4....they worked 4 hrs
5 0
3 years ago
Read 2 more answers
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