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MrRissso [65]
4 years ago
7

Plz help me get the answer ASAP please I been stuck on these

Mathematics
2 answers:
nika2105 [10]4 years ago
6 0

\frac{1}{2}y\leq -7     Multiply 2/1 or 2 on both sides to get "y" by itself

(2)\frac{1}{2}y\leq -7(2)

y ≤ -14


tino4ka555 [31]4 years ago
4 0

Answer:

<h2>y ≤ -14</h2>

Step-by-step explanation:

\dfrac{1}{2}y\leq-7\qquad\text{multiply both sides by 2}\\\\2\!\!\!\!\diagup^1\cdot\dfrac{1}{2\!\!\!\!\diagup_1}y\leq(2)(-7)\\\\y\leq-14

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Answer:

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Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

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solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

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Using the zero factor principle

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x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

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