Answer:
Yes, It is improper.
Step-by-step explanation:
<em>Your answer is correct. The limits of integration are finite. The integrand is not continuous on [1, ∞). At least one of the limits of integration is not finite. The integrand is continuous on [1, ∞).</em>
It is true because a rational function is defined as those functions where the variable is placed in the denominator, which must be restricted, because all denominators cannot be equal to zero, other wise it would be undetermined
The integers are called the opposites because they are on the opposite side of zero.
1. The area of the photograph is:
A=LxW
A is the area of the photograph (A=54 in²).
L is the lenght of the photograph (L=12-4x).
W is the widht of the photograph (W=12-2x)
2. When you substitute these values into the formula A=LxW, you obtain:
A=LxW
54=(12-4x)(12-2x)
3. When you apply the distributive property, you have:
54=144-24x-48x+8x²
8x²-72x+144-54=0
4. Finally, you obtain a quadratic equation for the area of the photo:
8x²-72x+90=0
5. Therefore, the answer is:
8x²-72x+90=0
Answer:
R'(3,-4)
Step-by-step explanation:
we know that
When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places
so
The rule of the reflection across the line y=x is equal to
(x,y) ------> (y,x)
we have
R(-4,3) ------> R'(3,-4)