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2 years ago

Is this correct ???? please help

Mathematics

1 answer:

Bond [772]2 years ago

4 0

Answer:

I do not think so.

Step-by-step explanation:

I believe the last two options should be swapped. You multiply in the second to last step, and in this problem you put what happens in the previous step in the next box so multiplication should be in the last box

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The equation of a circle in general form is x2+y2+20x+12y+15=0 . What is the equation of the circle in standard form?

mestny [16]

Answer:

(x)²+(y)²=0

Step-by-step explanation:

6 0

3 years ago

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Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c

natali 33 [55]

Answer: By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

In which A≡(6,8), B≡(2,2) and C≡(8,4)

And, D and E are the mid points of the line segments AB and BC respectively.

Prove: DE║AC and DE = AC/2

Proof:

Since, And, D and E are the mid points of the line segments AB and BC respectively.

Therefore, By mid point theorem,

coordinate of D are $(\frac{2+6}{2} , \frac{2+8}{2} ) = (\frac{8}{2} , \frac{10}{2} )= (4,5)$

Coordinate of E are $(\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)$

By the distance formula,

$DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}$

$AC=\sqrt{(8-6)^2+(4-8)^2}=2\sqrt{5}$

By the slope formula,

Slope of AC = $\frac{4-8}{8-6} = \frac{-4}{2} = -2$

Slope of DE = $\frac{3-5}{5-4} = \frac{-2}{1} = -2$

Statement Reason

1. The coordinate of D are (4,5) and 1. By the midpoint formula

the coordinate of E are (5,3)

2. The length of DE = √5 2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the 3. By the slope formula

slope of AC = -2

4. DE║AC 4. Slopes of parallel lines are equal

7 0

3 years ago

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A box is x to inches high,(2x+3)inches wide, and (2x+5) of inches long. In terms of x, what is the volume (v) of the box?

Advocard [28]

Answer:

The volume of the box is $V=(4x^3+16x^2+15x)\ in^3$

Step-by-step explanation:

we know that

The volume of the box is equal to

$V=LWH$

where

L is the length of the box in inches

W is the width of the box in inches

H is the height of the box in inches

we have

$L=(2x+5)\ in\\W=(2x+3)\ in\\H=x\ in$

substitute in the formula

$V=(2x+5)(2x+3)x$

$V=(4x^2+6x+10x+15)(x)$

$V=(4x^2+16x+15)(x)$

$V=(4x^3+16x^2+15x)\ in^3$

6 0

2 years ago

What is the sum of 13+52 as the product of their GCF and another sum

vova2212 [387]

GCF(13; 52) = 13

13 = 13 · 1
52 = 13 · 4

13 + 52 = 13 · 1 + 13 ·4 = 13·(1 + 4)

Used distributive property: a(b + c) = ab + ac

4 0

2 years ago

20 POINTS!

alukav5142 [94]

I think it was √(a^2+b^2. I think.

8 0

2 years ago