find five consecutive even integers if the sum of the first and fifth is 2 less than 3 times the fourth.

1 answer:

3 0

$2a,2a+2,2a+4,2a+6,2a+8-\ \ five\ consecutive\ even\ integers\\\\
2a+2a+8+2=3(2a+6)\\\\
2a+2a+10=6a+18\\\\
4a+10=6a+18\ \ \ |Subtract\ 4a\\\\
10=2a+18\ \ \ |Subtract\ 18\\\\
10-18=2a\\\\
-8=2a\ \ \ |Divide\ by\ 2\\\\
a=-4\\\\
\boxed{Numbers:\
-4,-2,0,2,4}$

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