Question

find five consecutive even integers if the sum of the first and fifth is 2 less than 3 times the fourth.

Answer 1

$2a,2a+2,2a+4,2a+6,2a+8-\ \ five\ consecutive\ even\ integers\\\\ 2a+2a+8+2=3(2a+6)\\\\ 2a+2a+10=6a+18\\\\ 4a+10=6a+18\ \ \ |Subtract\ 4a\\\\ 10=2a+18\ \ \ |Subtract\ 18\\\\ 10-18=2a\\\\ -8=2a\ \ \ |Divide\ by\ 2\\\\ a=-4\\\\ \boxed{Numbers:\ -4,-2,0,2,4}$