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3 years ago

find five consecutive even integers if the sum of the first and fifth is 2 less than 3 times the fourth.

1 answer:

3 0

$2a,2a+2,2a+4,2a+6,2a+8-\ \ five\ consecutive\ even\ integers\\\\
2a+2a+8+2=3(2a+6)\\\\
2a+2a+10=6a+18\\\\
4a+10=6a+18\ \ \ |Subtract\ 4a\\\\
10=2a+18\ \ \ |Subtract\ 18\\\\
10-18=2a\\\\
-8=2a\ \ \ |Divide\ by\ 2\\\\
a=-4\\\\
\boxed{Numbers:\
-4,-2,0,2,4}$

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3 years ago

PLEASE HELP!!!!

Mazyrski [523]

<h3>Answer: A. 18</h3>

===========================================================

Explanation:

The set A U B represents the list of items that are either in set A, set B or both sets at the same time. The "U" is the union symbol.

Set A U B looks like this

A U B = {-10, 8, 12, 26, 29, -8, - 1,5, 26, 36}

I basically started with set A, then tacked on the stuff in set B shown in bold.

From here, we toss out the duplicate item 26 and we can optionally sort the set

A U B = {-10, -8, -1, 5, 8, 12, 26, 29, 36}

We see that the number 18 is not in this final set, which is why choice A is the answer.

--------------------

Put another way: the number 18 is neither in set A nor set B, so it cannot be in set A U B.

Something like -10 is in set A, so it's going to be in set A U B as well. We can rule out choice B for this reason. Choices C and D follow a similar idea as choice B.

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3 years ago

Jrian"s plane was supposed to leave at 1:25. If he arrived one hour and 52 minutes early, what time did he arrive at the airport

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First, 1:25 to 1:00 would be 25 minutes early. Therefore, you do 52 - 25 = 33. One hour and 33 minutes early now. Then, you do one hour before 1:00 which would be 12:00. Finally, you would do 60 - 33 because 12:00 is technically 12:60. 60 - 33 = 27. The answer is 11:27.

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3 years ago

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Step-by-step explanation:

Let

x -----> the number of ads

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Subtract 20 both sides

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4 years ago

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Answer:

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