Answer:
The new width = 2 inches
Step-by-step explanation:
Original dimensions of the rectangular photo:
Length : width = 8 inches : 4 inches
Reduced dimensions of the rectangular photo:
Let
x = the new width
Length : width = 4 inches : x inches
Equate both dimensions to get the value of x
Length : width
8 inches : 4 inches = 4 inches : x inches
8 / 4 = 4 / x
Cross product
8 * x = 4 * 4
8x = 16
x = 16/8
x = 2 inches
The new width = 2 inches
Answer:
(2, 14), (3, 7)
Step-by-step explanation:
The way these angles are numbered, corresponding angle numbers differ by 4, 8, or 12.
Corresponding angles are ...
Angle 2 and Angle 14 . . . . . . numbers differ by 12
Angle 3 and Angle 7 . . . . . . . numbers differ by 4
_____
If a given angle is Northwest of the intersection, any corresponding angle will also be Northwest of its intersection. Corresponding angles are ...
northwest: {1, 5, 9, 13}
northeast: {2, 6, 10, 14}
southeast: {3, 7, 11, 15}
southwest: {4, 8, 12, 16}
Any pair of numbers from the same set will be corresponding angles.
Answer:
Step-by-step explanation:
you need to use the proportions
x=(3*5)/8=15/8
Answer:
15% increase
Step-by-step explanation:
2750... 10% of that is 275, add 275 to 2750 is 3025. 1% of 2750 is 27.50, you times that by 5, which is 137.50 and add that to 3025 giving you 3162.50, add the 10% with the 5% gives you 15%, that's the increase.
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.