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3 years ago

Edwin says that he can show a figure base an congruent triangular

Mathematics

2 answers:

Georgia [21]3 years ago

4 0

We need more information. this seems like a part of a question. is there any more?

Anuta_ua [19.1K]3 years ago

3 0

That's great <span>that he can show a figure base an congruent triangular</span>

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1) A bag contains six red marbles and eight blue marbles. You randomly pick a marble and then pick a second marble without retur

Elena-2011 [213]

Answer:

You would have 4 red marbles and 8 blue marbles since you didn't return the ones you took out to the bag.

Step-by-step explanation:

6 - 2 = 4

The 8 would stay the same

There for you would have 4 red marbles and 8 blue marbles left in the bag. Totalled you have 12 marbles in the bag and 2 out of the bag. (8 + 4 = 12)

Including the marbles in and out of the bag you have 14 marbles. The 12 inside the bag + the 2 outside of the bag = 14 marbles totalled.

5 0

2 years ago

What is an equation of the line that passes through the points (3, 4) and (-4, -3)? Put your answer in fully reduced form.

Alexxx [7]

Answer:

y=x+1 is right answer .

6 0

2 years ago

What is the given output of the given input f(x)=-3x+6 find 2

FinnZ [79.3K]

F(x)= y
this is the equation that explains the problem<span />

7 0

3 years ago

How do I solve this?

prisoha [69]

$y = - 7 \\ x = 3$

7 0

2 years ago

Solve:

STatiana [176]

The solutions to the equation $3-k=\sqrt{3k+1}$ are k = 1 and 8

The given equation is:

$3-k=\sqrt{3k+1}$

Square both sides of the equation

$(3-k)^2=3k+1$

Expand the left side of the equation above

$(3-k)^2=3k+1\\\\(3-k)(3-k)=3k+1\\\\3^2-3k-3k+k^2=3k+1\\\\9-6k+k^2=3k+1$

Write the quadratic equation in standard form

$k^2-6k-3k+9-1=0\\\\k^2-9k+8=0\\\\$

Factor the quadratic equation

$(k-8)(k-1)=0$

Use the zero product property

k - 8 = 0

k = 8

k - 1 = 0

k = 1

The solutions to the equation $3-k=\sqrt{3k+1}$ are k = 1 and 8

Learn more here: brainly.com/question/25840704

8 0

2 years ago

Read 2 more answers