Given that t<span>here
are 20 light bulbs in 5 packages.
The table to find the rate
that gives you the number of light bulbs in 3 packages is given as follows:
![\begin{tabular} {|c|c|c|c|c|c|} Light bulbs&4&8&12&16&20\\[1ex] Packages&1&2&3&4&5 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0ALight%20bulbs%264%268%2612%2616%2620%5C%5C%5B1ex%5D%0APackages%261%262%263%264%265%0A%5Cend%7Btabular%7D)
Three different ways in which the rate can be written are:
12 light bulbs to 3 packages
12 light bulbs : 3 packages
12 light bulbs / 3 packages
</span>
Answer:
64 sodas and 32 hot dogs
Step-by-step explanation:
192 divide by 2 = 96. 96 divide by 3 = 32. 32 +32 =64 because there was 2 times as many sodas sold.64 +32=96.
I think the answer is a. -3x^2-x-5
Answer:
h = √91 cm
Step-by-step explanation:
Apply pythagorean theorem, a² + b² ° c².
Where,
a = ½(6) = 3 cm
b = h
c = 10 cm
Plug in the values
3² + h² = 10²
9 + h² = 100
9 + h² - 9 = 100 - 9
h² = 91
h = √91 cm
Answer:
34%
Step-by-step explanation:
Given that the distribution of daily light bulb request replacement is approximately bell shaped with ;
Mean , μ = 45 ; standard deviation, σ = 3
Using the empirical formula where ;
68% of the distribution is within 1 standard deviation from the mean ;
95% of the distribution is within 2 standard deviation from the mean
Lightbulb replacement numbering between ;
42 and 45
Number of standard deviations from the mean /
Z = (x - μ) / σ
(x - μ) / σ < Z < (x - μ) / σ
(42 - 45) / 3 = -1
This lies between - 1 standard deviation a d the mean :
Hence, the approximate percentage is : 68% / 2 = 34%
