Answer:
Infinite amount of solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -2x + 4
2x + y = 4
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2x + (-2x + 4) = 4
- Combine like terms: 4 = 4
Here we see that 4 does indeed equal 4.
∴ the systems of equations has an infinite amount of solutions.
Answer:
0 - 10x + 1.5
Step-by-step explanation:
-2(5x - 0.75)
Expand the bracket
-10x + 1.5
0 - 10x + 1.5 is the equivalent expression
1-10 is the answer to the question
Answer:
Part A: 2k(2c2+5(2)-8c-20)
Part B: sorry i don't know how to do this part
Step-by-step explanation:
Part A, you divide each number by 2 first so you get a simplified version of each number. Then, you will quickly realize that the varible k is similar in all of the numbers then you remove that and put it with the 2 outside the (). Hope you understood my explination.
The answer to your question is 15