Order from least to greatest. 0.29,2/7 , 25%, 0.2
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The values of BMW after 2 years and 4 years according to the EXPONENTIAL FUNCTION are $33,462 and $20,358.28
Using the parameters given, we define an decreasing exponential function :
Where,
= initial amount ; r = Rate ; t = time ; A = final amount
Value after 2 years :
t = 2
A = 55000(1 - 0.22)²
A = 55000(0.78)²
A = $33,462
Value after 4 years :
t = 4
A = 55000(1 - 0.22)^4
A = 55000(0.78)^4
A = $20,358.28
Therefore, the value of BMW after 2 years and 4 years $33,462 and $20,358.28 respectively.
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Answer:
a=-1 b=3 h=-4 k=5. Hope this helps.
Step-by-step explanation:
We need to find transformations from f(x) to g(x).
K is formula usually means vertical shift. Vertical shift are usually at right end of formula. f(x) has a vertical shift of zero, while g(x) vertical shift is 5. So our k is 5.
h represent our horizontal shift in a equation.
Our horizontal shift is opposite of the sign given.
F(x) has no hoeinzontal shift, while g(x) has x+4.
Set x+4=0
so our h is -4.
B represent our horizontal compression or stretch.
Our horizontal compression/stretch is reciprocal of our b given.
f(x) has no compression or stretch, while g(x) has 1/3x.
Set 1/3x to one.
so our b is 3.
A represents the vertical compression/ stretch. F(x) doesnt have one but G(x) does.
Since it has just a negative sign in front of it, the compression is -1 so a=-1
As the fellow above said, the particle does make a U-turn at the vertex, and we can find that out by getting the derivative of s(t) and zeroing it out to get the point of the horizontal tangent.
Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.
the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.
Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.
the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.