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Stella [2.4K]
4 years ago
10

For each group of three forces below, determine whether the forces in each pair are pulling at right angles to each other. 13 lb

, 35 lb, resultant force 30 lb, no; 20 lb, 15 lb, resultant force 25 lb, yes 13 lb, 35 lb, resultant force 30 lb, yes; 20 lb, 15 lb, resultant force 25 lb, no 13 lb, 35 lb, resultant force 30 lb, no; 20 lb, 15 lb, resultant force 25 lb, no 13 lb, 35 lb, resultant force 30 lb, yes; 20 lb, 15 lb, resultant force 25 lb, yes
Mathematics
1 answer:
Alex17521 [72]4 years ago
7 0
From the given problem, I gather that there are only two groups of forces. These are:
13 lb, 35 lb, resultant force 30 lb
20 lb, 15 lb, resultant force 25 lb

We use the pythagorean theorem to determine if the three forces are grouped correctly, such that the resultant force is the hypotenuse.

Resultant Force = √(a² + b²)

So, for the first group,
30 ? √(13² + 35²)
30 ≠ 37.33
Thus, the first group does not pull at right angles to each other.

For the second group,
25 ? √(20² + 15²)
25 = 25
Thus, the second group does pull at right angles to each other.

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5/7 

when you see the word "of" that means multiplication 

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Answer:

B. 3

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4 years ago
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Scrat [10]
Question 1:

Use the Pythagorean theorem.

If c^2\ \textless \ a^2+b^2, then the angle is acute.
If c^2=a^2+b^2, then the angle is right.
If c^2\ \textgreater \ a^2+b^2, then the angle is obtuse.

a=18
b=80
c=81

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\boxed {c^2\ \textless \ a^2+b^2}

Thus, the angle is acute.

Question 2:

Take the square root of the area to get the side length.

\sqrt{200} = \sqrt{100*2} =10 \sqrt{2}

That's the side length. Since we have a 45-45-90 right triangle if we divide the square across its diagonal, we just multiply the side length by the square root of 2 in order to get the diagonal length.

10 \sqrt{2} *  \sqrt{2}
=20

Your answer is 20 m. Hope this helps! :)
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