C=2πr
r=C/(2π), now the surface area is:
A=4πr^2, using r found above we have:
A=4πC^2/(4π^2)
A=C^2/π, we are given that C=28 so:
A=28^2/π in^2
A=784/π in^2
A≈250 in^2 (to nearest square inch)
Answer:
Use a compass to draw two equal arcs ...
Step-by-step explanation:
The attached diagram shows the construction of an angle bisector. First you draw arc DE, then arcs from D and E with the same radius that cross at F.
So, the step on your list is, "use a compass to draw two equal arcs from the intersection points of a previous arc and the legs."
5(5r-7)=-185
25r - 35 = - 185
25r = - 150
r = - 6
Considering the definition of an equation and the way to solve it, the total cost of the shoes is 0.20×(x-15).
<h3>Definition of equation</h3>
An equation is the equality existing between two algebraic expressions connected through the equals sign in which one or more unknown values, called unknowns, appear in addition to certain known data.
The members of an equation are each of the expressions that appear on both sides of the equal sign while the terms of an equation are the addends that form the members of an equation.
<h3>Total cost in this case</h3>
Being "x" the price of the shoes, and knowing that:
- you apply a discount of $15 first → x -15
- you apply a discount of 20% through a second discount (
- (applied on the first discount already made) → 20%×(x-15) → 0.20×(x-15)
the equation in this case is:
<u><em>Total cost= 0.20×(x-15)</em></u>
Finally, the total cost of the shoes is 0.20×(x-15).
Learn more about equations:
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The first thing we must do for this case is to find the scale factor based on the dimensions of the figures.
The largest figure is 7 inches tall. Each of the other figures is 1 inch shorter than the next larger figure.
We have then that the smallest figure has a height of 1 inch.
The scale factor is:
k = (smallest figure) / (largest figure) = 1/7
k = 1/7
The surface area of the smaller figure is:
A = k ^ 2 * (A ')
Where
A ': surface area of the largest figure.
Substituting:
A = (1/7) ^ 2 * (588)
A = 12 in ^ 2
Answer:
The surface area of the smallest figure is:
A = 12 in ^ 2