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Readme [11.4K]
3 years ago
8

Please I really need help on this matter question

Mathematics
2 answers:
Romashka [77]3 years ago
8 0
<span>y=(x+8)^3+9

y=(x+8)(x^2+8x+16) + 9

y=(x+8)(x+4)(x+4)+9

0=(</span>x+8)(x+4)(x+4)+9

x+8=0

x=-8

x+4=0

x=-4

I believe the answer is 2

Katarina [22]3 years ago
6 0
The answer should be 1. Keep in mind that all cubic curves will always have at least 1 real zero. The embedded image is a graph of y=(x+8)³+9


The second answer should be y=xx^{4}-6xx^{3}+6xx^{2}-6x+5 (the last answer choice), as seen by the second image. 



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Step-by-step explanation:

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2. (10.03)
faust18 [17]

This question is incomplete because it was not written properly

Complete Question

A teacher gave his class two quizzes. 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first one passed the second quiz? (2 points)

a) 20%

b) 40%

c) 60%

d) 75%

Answer:

d) 75%

Step-by-step explanation:

We would be solving this question using conditional probability.

Let us represent the percentage of those who passed the first quiz as A = 80%

and

Those who passed the first quiz as B = unknown

Those who passed the first and second quiz as A and B = 60%

The formula for conditional probability is given as

P(B|A) = P(A and B) / P(A)

Where,

P(B|A) = the percent of those who passed the first one passed the second

Hence,

P(B|A) = 60/80

= 0.75

In percent form, 0.75 × 100 = 75%

Therefore, from the calculations above, 75% of those who passed the first quiz to also passed the second quiz.

3 0
3 years ago
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ruslelena [56]
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3 years ago
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