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Readme [11.4K]
3 years ago
8

Please I really need help on this matter question

Mathematics
2 answers:
Romashka [77]3 years ago
8 0
<span>y=(x+8)^3+9

y=(x+8)(x^2+8x+16) + 9

y=(x+8)(x+4)(x+4)+9

0=(</span>x+8)(x+4)(x+4)+9

x+8=0

x=-8

x+4=0

x=-4

I believe the answer is 2

Katarina [22]3 years ago
6 0
The answer should be 1. Keep in mind that all cubic curves will always have at least 1 real zero. The embedded image is a graph of y=(x+8)³+9


The second answer should be y=xx^{4}-6xx^{3}+6xx^{2}-6x+5 (the last answer choice), as seen by the second image. 



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Answer:

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(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let <em>X</em> = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts <em>n</em> = 8 potential customers per day.

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The probability mass function of <em>X</em> is:

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P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488

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(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

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              =1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

E(X)=np=8\times 0.10=0.80

Thus, the expected number of sales per day is 0.80.

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