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Andrej [43]
4 years ago
7

How do we express one-half of the difference of a number cubed and one?

Mathematics
2 answers:
Colt1911 [192]4 years ago
4 0

Answer:

1/2(x^3 - 1) or we could write it as (x^3 - 1) / 2.

Step-by-step explanation:

A number cubed is x^3. Difference of this and 1 is x^3 - 1.

Finall we have 1/2 of this:

= 1/2(x^3 - 1) or we could write it as (x^3 - 1) / 2.

devlian [24]4 years ago
4 0

Answer:

\frac{x^3-1}{2}

Step-by-step explanation:

We must follow what the statement asks us, starting from the last thing and going forward from there.

A number cubed: x^3

The difference of a number cubed and one: x^3-1

And finally:

one-half of the difference of a number cubed and one, this would be one half of the expression we already found:

\frac{x^3-1}{2}

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densk [106]

Answer:

6(4 + 5)

Step-by-step explanation:

You are supposed to use reverse distributive proper and pull out the greatest common multiple. Since 6 both multiply's 4 into 24 and 5 into 30 we can pull that out and we are left with this:

6(4 + 5)

8 0
3 years ago
Read 2 more answers
Which of these is equivalent to -x &lt; 8?:<br> x &lt; 8<br> x &lt; -8<br> x &gt; 8<br> x &gt; -8
adell [148]

Answer:

x>-8

Step-by-step explanation:

multiply both sides with -1

6 0
4 years ago
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The sum of the ages of Mrs. Spelman and Mr. Murphy are 78 years. Six years from now Mrs. Spelman's age will be equal to 6 times
Studentka2010 [4]

Answer:

  • Mrs Spelman: 71 1/7
  • Mr/Ms Murphy: 6 6/7

Step-by-step explanation:

There are no integer solutions to the problem as posed. (We suspect a typo, that the intention is 3 years from now, or that the ratio will be 5:1.)

Let m represent Murphy's age now. Then 78-m represents Spelman's age now, and the ratio in 6 years will be ...

  78 -m +6 = 6(m +6)

  84 -m = 6m +36 . . . . . collect terms

  48 = 7m . . . . . . . . . . . . add m-36

  48/7 = m = 6 6/7 . . . . . divide by the coefficient of m

Then Spelman's age now is ...

  78 -m = 78 -6 6/7 = 71 1/7

Spelman is 71 1/7; Murphy is 6 6/7.

_____

If the ratio is 6:1 in 3 years, then Murphy is 9 and Spelman is 69.

If the ratio is 5:1 in 6 years, then Murphy is 9 and Spelman is 69.

_____

<em>Alternate solution method</em>

I find it easiest to add 12 years to the total (each ages by 6 years), which will give a total age of 90 in 6 years. At that time, Murphy is 1/7 of the total of ages, so dividing that sum into parts with the appropriate ratio gives m'=90/7=12 6/7; s'=77 1/7. So, m=6 6/7; s=71 1/7.

_____

<em>Comment on the problem</em>

We think there is a "typo" because the ratio of 6:1 means the future total should be a multiple of 7. Of course, 78+6 =84 is a multiple of 7, but adding 6 to the total will occur in 3 years, not 6 years.

4 0
3 years ago
HAY IN THE MIDDLE OF THE BARN: There are one thousand and forty-one bales of hay in the barn. Farmer John is getting ready for F
snow_tiger [21]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

Initial number of bales of hay = 1041 bales

After stacking more bales in the barn:

Total number of bales after stacking = 2,358 bales

Equation for scenario b

Initial bales + added bales = total number of bales after stacking

Let added bales = b

1,041 + b = 2,357

Added bales = Newly stacked bales:

1041 + b = 2,357

b = 2357 - 1041

b = 1,316

The stacked bales of hay stacked to join the initial is. 1,316 bales

3 0
3 years ago
An Ice cream shop offers the following toppings:
GenaCL600 [577]
The corect answer is 15.

This is a combination of 6 objects taken 4 at a time:

_6C_4=\frac{6!}{4!2!}=\frac{720}{48}=15
5 0
4 years ago
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