Answer:
270 tickets are sold for the Sunday show.
Step-by-step explanation:
Given:
Two-fifth of the total tickets are sold for the Saturday show.
Tickets sold for the Saturday show = 240
Three times as many tickets are sold for the Sunday show as for the Friday show. This means that tickets sold for Sunday show is three times that for Friday.
Let the tickets sold for Friday show be 'x'. Therefore, tickets sold for the Sunday show is given as 3 times of 'x' = 
Total tickets sold = Sum of all tickets sold on Friday, Saturday and Sunday.
Total tickets sold = 
Total tickets sold = 
Now, as per question, two-fifth of the total tickets are sold for Saturday show and ticket sold on Saturday is 240. So,
Therefore, tickets sold for the Sunday show = 
Hence, 270 tickets are sold for the Sunday show.
An irrational number is one that can’t be expressed as a simple fraction.
For instance, the first few digits of the square root of two is written as 1.414213562373095... The digits keep going and cannot be expressed as a fraction. But think of 0.33333... That can easily be written as one-third. The distinguishing feature is that there’s no pattern in the digits for the square root of two.
The first two options are integer fractions. We rule those out immediately. The square root of four is tempting, but realize that it is just equal to two. We come to π (pi).
Arguably the most famous irrational number is π, which starts off as 3.14159265358979... Here, there is again no pattern and the digits extend forever. This meets our definition of our irrational.
Explanation:
Factoring to linear factors generally involves finding the roots of the polynomial.
The two rules that are taught in Algebra courses for finding real roots of polynomials are ...
- Descartes' rule of signs: the number of positive real roots is equal to the number of coefficient sign changes when the polynomial is written in standard form.
- Rational root theorem: possible rational roots will have a numerator magnitude that is a divisor of the constant, and a denominator magnitude that is a divisor of the leading coefficient when the coefficients of the polynomial are rational. (Trial and error will narrow the selection.)
In general, it is a difficult problem to find irrational real factors, and even more difficult to find complex factors. The methods for finding complex factors are not generally taught in beginning Algebra courses, but may be taught in some numerical analysis courses.
Formulas exist for finding the roots of quadratic, cubic, and quartic polynomials. Above 2nd degree, they tend to be difficult to use, and may produce results that are less than easy to use. (The real roots of a cubic may be expressed in terms of cube roots of a complex number, for example.)
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Personally, I find a graphing calculator to be exceptionally useful for finding real roots. A suitable calculator can find irrational roots to calculator precision, and can use that capability to find a pair of complex roots if there is only one such pair.
There are web apps that will find all roots of virtually any polynomial of interest.
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<em>Additional comment</em>
Some algebra courses teach iterative methods for finding real zeros. These can include secant methods, bisection, and Newton's method iteration. There are anomalous cases that make use of these methods somewhat difficult, but they generally can work well if an approximate root value can be found.
Answer:
1410ft²
Step-by-step explanation:
20 * 12 * 2 + [62 * (15 + 12)] =
480 + (62 * 15) =
480 + 930 =
1410ft²
Greater
If we get common denominators
1/2=15/30
3/15=6/30
15>6 therefore 1/2>3/15
