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4 years ago

12

These are 3 consecutive integers such that 3 times the sum of the first and third is 5 times the second. What is the third integ

er?

1 answer:

Fynjy0 [20]4 years ago

8 0

X=10 is the answer !!!!!!!!!!

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Find the 20th term in the sequence, where the first term is -2 and the common ratio is-2.

geniusboy [140]

Answer:

Step-by-step explanation:

(1)

a1=-2

r=-2

$a_{20}=(-2)(-2)^{20-1}=-2(-2)^{19}=2^{20}=1048576\\(2)\\a_{1}=1000\\r=\frac{200}{1000} =\frac{1}{5} \\a_{8}=1000(\frac{1}{5} )^{8-1}=1000(.2)^7=0.0128\\(3)\\a_{1}=2\\a_{3}=50\\a_{2}=\sqrt{2*50} =10\\r=\frac{10}{2} =5$

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3 years ago

You were playing fetch with your dog an accidentally threw the toy and it

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Answer:

8.1

Step-by-step explanation:

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3 years ago

Which of the following statements are true regarding functions?<br><br> Check all that apply.

Alex

Answer:

The horizontal line test may be used to determine whether a function is one-to-one.
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Step-by-step explanation:

3 0

2 years ago

Which values for x and y make the statement (x + 5)(y - 6) = 0 true?

-BARSIC- [3]

<span> $||Solving \ for \ x. ||$ </span>

$(x + 5)(y - 6) = 0$

$(x + 5)(y - 6) = 0 :x$

$
x+5=0
 
$ $|Divide \ both \ sides \ by \ y-6|$

$
x=-5
 
$ $|Subtract \ 5 \ from \ both \ sides|$

$||Solving \ for \ y. ||$

$
y-6=0
 
$ $|Divide \ both \ sides \ by \ x+5|$

$
y=6
 
$

$Solution =\ \textgreater \ x = -5, y = 6$

6 0

3 years ago

Find the area of each parallelogram plz help

xxTIMURxx [149]

Answer: The area of the parallelogram is:
_______________________________________________________
$\frac{9393}{8}$ in² = 1174 ⅛ in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
A = base * height = b * h ;

From the figure (from the actual "question"):
_______________________________________
b = 50.5 in.

h = 23.25 in.
____________________________________________________________
Method 1) A = b * h =

= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 <span>⅛ .
</span>____________________________________________________________
Method 2) A = b * h =

= (50 ½ in) * (23 <span>¼ in) =

= (</span> $\frac{101}{2}$ in) * ( $\frac{93}{4}$ <span> in) ;
</span>___________________________________________________________
Note: "50 ½ " = [(50*2) + 1 ] / 2 = $\frac{101}{2}$ ;

Note: "23 ¼ " = [(23*4) + 1 ] / 4 = $\frac{93}{4}$ ;
____________________________________________________________
→ A = ( $\frac{101}{2}$ in) * ( $\frac{93}{4}$ in) ;

→ A = $\frac{(101*93)}{(2*4)}$ in² = $\frac{9393}{8}$ in² ;

→ A = (9393/8) in² =

→ A = $\frac{9393}{8}$ in² = 1174 ⅛ in² = 1174.125 in² .
________________________________________________________

5 0

3 years ago