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Archy [21]
4 years ago
12

These are 3 consecutive integers such that 3 times the sum of the first and third is 5 times the second. What is the third integ

er?
Mathematics
1 answer:
Fynjy0 [20]4 years ago
8 0
X=10 is the answer !!!!!!!!!!
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Amelia ,Hayden and Sophie did a test the total for the test was 75 marks Amelia got 56% of 75 marks Hayden got 8/15 0f the 75 ma
boyakko [2]

Step-by-step explanation:

Amelia got 56% of 75 so

(56/100)*75=(56*75)/100=4200/100=42

Hayden got 8/15 of 75 so

(8/15)*75=(8*75)/15=600/15=40

and Sophie that got 43 out of 75

so we see that Sophie got the highest points.

6 0
3 years ago
Read 2 more answers
Sarah is carrying out a series of experiments which involve using mcreasing amounts of a chemical. In the
Marianna [84]

Sarah is carrying out a series of experiments which involve using increasing amounts of a chemical. In the  first experiment she uses 6g of the chemical and in the second experiment she uses 7.8 g of the chemical

(i)Given that the amounts of the chemical used form an arithmetic progression find the total amount of  chemical used in the first 30 experiments

(ii)Instead it is given that the amounts of the chemical used for a geometric progression. Sarah has a  total of 1800 g of the chemical available. Show that the greatest number of experiments possible satisfies the inequality: 1.3^N \leq 91 and use logarithms to calculate the value of N.

Answer:

(a)963 grams

(b)N=17

Step-by-step explanation:

(a)

In the first experiment, Sarah uses 6g of the chemical

In the second experiment, Sarah uses 7.8g of the chemical

If this forms an arithmetic progression:

First term, a =6g

Common difference. d= 7.8 -6 =1.8 g

Therefore:

Total Amount of  chemical used in the first 30 experiments

S_n=\dfrac{n}{2}[2a+(n-1)d] \\S_{30}=\dfrac{30}{2}[2*6+(30-1)1.8] \\=15[12+29*1.8]\\=15[12+52.2]\\=15*64.2\\=963$ grams

Sarah uses 963 grams in the first 30 experiments.

(b) If the increase is geometric

First Term, a=6g

Common ratio, r =7.8/6 =1.3

Sarah has a total of 1800 g

Therefore:

Sum of a geometric sequence

S_n=\dfrac{a(r^N-1)}{r-1} \\1800=\dfrac{6(1.3^N-1)}{1.3-1} \\1800=\dfrac{6(1.3^N-1)}{0.3}\\$Cross multiply\\1800*0.3=6(1.3^N-1)\\6(1.3^N-1)=540\\1.3^N-1=540\div 6\\1.3^N-1=90\\1.3^N=90+1\\1.3^N=91

Therefore, the greatest possible number of experiments satisfies the inequality

1.3^N \leq 91

Next, we solve for N

Changing 1.3^N \leq 91 to logarithm form, we obtain:

N \leq log_{1.3}91\\N \leq \dfrac{log 91}{log 1.3}\\ N \leq  17.19

Therefore, the number of possible experiments, N=17

3 0
3 years ago
According to a medical study, 15% of people will experience an adverse side effect
ahrayia [7]

Answer:

c

Step-by-step explanation: trust me

6 0
3 years ago
Read 2 more answers
Y=-2x+5 how do you solve?
Alex73 [517]

Answer:

here are the coordinates :

(0,5) and (1,3)

3 0
3 years ago
Can any one you help me with this ?
OLEGan [10]

NUE is 30° LUN is 60° EUS is 30° LUE is 90° LUS is 120°

Step-by-step explanation:

NUE is given

LUN was from the 90° angle LUE but just minus 30°

EUS is honestly a guess :/

LUE is obviously 90° as we used it earlier

LUS was the 90° plus the EUS

7 0
3 years ago
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