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Sergeu [11.5K]
1 year ago
15

Select ALL expressions that have a value less than 9.

Mathematics
2 answers:
GrogVix [38]1 year ago
6 0

Answer:

What is this?

Can't understand anything!

earnstyle [38]1 year ago
3 0

Answer : what is this question?

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A tea‑drinking Canadian friend of yours claims to have a very refined palate. She tells you that she can tell if, in preparing a
wlad13 [49]

Answer:

20

Step-by-step explanation:

There are 20 ways to select 3 cups from the 6 cups.

This can be calculated using formula nCr

Where,

n = objects

r = sample

Calculating 6C3 using calculator that is 20.

6 0
2 years ago
Please help it due ASAP <br> Pls SHOW WORKINGS also.
marusya05 [52]

Answer:

D

Step-by-step explanation:

Angle 5 is equal to angle 8 because the two angles are an alternate interior angle. We already know that angle 7 and 8 are supplementary because it's adjacent to each other on a straight line. So, since angle 5 and 8 is equal to each other, angle 5 is also supplementary to angle 7.

4 0
3 years ago
Find the midpoint of the segment between (6,7) and (6,-5)
Norma-Jean [14]

Answer:

(6,1)

Step-by-step explanation:

midpoint = ((x2+x1),(y2+y1)/2)

= (6+6)/2, (-5+7)/2

= 12/2, 2/2

= 6,1

3 0
3 years ago
Read 2 more answers
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
Katie's bank statement shows a closing balance of $178.11. There are no outstanding checks or deposits. Her checkbook shows a ba
castortr0y [4]
Overdraft fee in the amount of 20.00
7 0
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