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4 years ago

2/3p-14=p+13 How do I solve this

2 answers:

7 0

Add 14 to both sides
2/3p=p+27

Subtract p from both sides
-1/3p= 27

Multiply both sides by -3
p= -81

Final answer: p=-81

Kryger [21]4 years ago

3 0

So here you just want to move all the like terms to either sides.

You can do this by first adding 14 to both sides.

2/3p - 14 = p + 13

+ 14 +14

2/3p = p + 27

And then by subtracting p from both sides

-1/3p = 27

And then dividing both sides by -1/3

p = -81

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It will hit the floor when h=0

-16t^2+14.8t+3.9=0

using the quadratic formula...

t=(-14.8±√468.64)/-32, since t>0

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4 years ago

After a car is purchased, the value of a new car decreases $4000 each year. After 3 years, the car is worth $18000.

Over [174]

Original - 4000x

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Original - 12000 = 18000 

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3 years ago

1. Tristan Sandino is selling his motorcycle. His friend, Rudy, is offering to pay cash in the amount of $8,800. Another friend,

mina [271]

1. The amortization formula can tell you the present value if the string of payments is made at the end of the month.
A = P(i/n)/(1 -(1 +i/n)^(-nt))
where A is the payment (200), P is the present value, n is the number of compoundings per year (12), and t is the number of years (4).
200 = P(.034/12)/(1 -(1 +.034/12)^-48)
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This matches the selection ...
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[Please note that an actual sale would probably require the first payment be made immediately, hence the present value would actually be $8,989.36.]

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4 years ago

Use the formula to solve the problem. Round to the nearest hundredth.

Zepler [3.9K]

Answer:

Volume of sphere = 4.186 cubic inches

Step-by-step explanation:

Radius of sphere = r = 1 inch

Volume of sphere = ?

The formula used is: $Volume\:of\:sphere=\frac{4}{3}\pi r^3$

Putting value of radius and π and finding volume:

$Volume\:of\:sphere=\frac{4}{3}\pi r^3\\Volume\:of\:sphere=\frac{4}{3}\times 3.14\times (1)^3\\Volume\:of\:sphere=\frac{4}{3}\times 3.14\times (1)^3\\Volume\:of\:sphere=4.186 \:cubic\:in$

So, Volume of sphere = 4.186 cubic inches

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3 years ago

The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.08

kvv77 [185]

Answer:

a) 44.93% probability that there are no surface flaws in an auto's interior

b) 0.03% probability that none of the 10 cars has any surface flaws

c) 0.44% probability that at most 1 car has any surface flaws

Step-by-step explanation:

To solve this question, we need to understand the Poisson and the binomial probability distributions.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson distribution with a mean of 0.08 flaws per square foot of plastic panel. Assume an automobile interior contains 10 square feet of plastic panel.

So $\mu = 10*0.08 = 0.8$

(a) What is the probability that there are no surface flaws in an auto's interior?

Single car, so Poisson distribution. This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.8}*(0.8)^{0}}{(0)!} = 0.4493$

44.93% probability that there are no surface flaws in an auto's interior

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws?

For each car, there is a $p = 0.4493$ probability of having no surface flaws. 10 cars, so n = 10. This is P(X = 10), binomial, since there are multiple cars and each of them has the same probability of not having a surface defect.