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Grace [21]
3 years ago
14

Why do antimicrobial agents active against mycobacteria have to be administered for months or years rather than the typical 10-3

0 days prescribed to treat other infections?
Biology
1 answer:
Eduardwww [97]3 years ago
3 0
Antimicrobial agents active <span>against mycobacteria have to be administered for months or years rather than the typical 10-30 days prescribed to treat other infections because mycobacteria reproduce very slowly.
So, over the period of time that mycobacteria reproduce, antimicrobial agents have to be taken so as to prevent these mycrobacteria from invading the body completely. Once their reproduction is completely prevented, antimicrobial agents don't have to be administered anymore.
</span>
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Legumes, a type of plant, require Rhizobia, a type of soil bacteria, to survive since these organisms fix nitrogen during photos
Romashka-Z-Leto [24]

The answer is: the legumes will extinct, too.


It is known that plants cannot directly use atmospheric nitrogen. But, some legumes have a symbiotic relationship with bacteria that live in their root system. These bacteria are called Rhizobia and have the ability of nitrogen-fixation. In the root nodules, they use atmospheric nitrogen to convert it into ammonia, and later to ammonium, which can be used by plants. When legumes die, nitrogen from their remaining is released back to the soil where it is available to the other plants.

So, if <span>Rhizobia suddenly became extinct, the symbiotic relationship between will be interrupted. The legumes will not be able to use atmospheric nitrogen without the help of Rhizobia, and eventually, they will extinct, too.</span>

8 0
3 years ago
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Anika [276]
The answer to that is Answer “B”
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3 years ago
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How many possible open reading frames (frames without stop codons) are there that extend through the following sequence? 5'... C
fenix001 [56]

Answer:

There are 4 reading frames without stop codons.

Explanation:

1) To find the possible reading frames you need to separate your sequence in codons (trios)  for the 5'-> 3' sense, first, excluding the first nucleotide, then excluding 2 nucleotides and then not excluding nucleotides.

5'... C TTA CAG TTT ATT GAT ACG GAG AAG G... 3'  NO STOP CODON

5'... CT TAC AGT TTA TTG ATA CGG AGA AGG... 3'  NO STOP CODON

5'... CTT ACA GTT TAT <u>TGA</u> TAC GGA GAA GG... 3'

2)Then you find the complementary sequence (which you already have)

3'... GAA TGT CAA ATA ACT ATG CCT CTT CC... 5'

3'... GA ATG TCA AAT AAC TAT GCC TCT TCC... 5'

3'... G AAT GTC AAA TAA CTA TGC CTC TTC C... 5'

3) Next, you have to obtain the reverse complementary

CCT TCT CCG TAT CAA TAA ACT GTA AG NO STOP CODON

CC TTC TCC GTA TCA ATA AAC TGT AAG NO STOP CODON

C CTT CTC CGT ATC AAT AAA CTG <u>TAA</u> G

4)Now you need to find start (AGT in terms of DNA) and stop codons(<u>TAA</u>, <u>TAG,</u> <u>TGA</u>, also in terms of DNA), in 5->3 and de reverse complementary.

<em />

<em>As you can see, you have for open reading frames that lack of stop codon, unfortunately, they also lack of AGT, the start codon.</em>

I added a table where you can find thestart and stop codons as well as the proteins that they translate to in terms of RNA.

I hope you find this information interesting and useful, good luck!

8 0
3 years ago
Which legs for a frog are used for jumping?
mario62 [17]
The hind legs, I believe. That's why they are longer and stronger.
7 0
3 years ago
Help biology!!!!!!!!!
adoni [48]

Answer:

I really don’t know

Explanation:

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