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Alexandra [31]
3 years ago
13

Edward wants to compare slope of two wake board ramps.The first ramp has the rise of 5 feet and run of 12 feet. The second has t

he rise of 6 feet and the run of 3 feet. Find the slope of each ramp. Which ramp is steeper?
Mathematics
1 answer:
xxMikexx [17]3 years ago
8 0

Answer:

Step-by-step explanation:

The formula for determining the slope of a ramp is expressed as

Slope = rise/run

The first ramp has the rise of 5 feet and run of 12 feet. This means that the slope of the first ramp is

Slope = 5/12 = 0.417

The second has the rise of 6 feet and the run of 3 feet. This means that the slope of the second ramp is

Slope = 6/3 = 2

The lower the run, the steeper the slope. This means that the second ramp is steeper than the first ramp.

This can be confirmed by calculating the angle formed by each ramp. To determine the angle formed by the ramp with the horizontal, we would apply we would apply

the tangent trigonometric ratio.

Tan θ = opposite side/adjacent side.

Considering the first ramp,

Tan θ = 5/12 = 0.417

θ = Tan^-1(0.417)

θ = 22.6°

Considering the second ramp,

Tan θ = 6/3 = 2

θ = Tan^-1(2)

θ = 63.4°

The second ramp forms a greater angle. Thus, it is steeper.

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8 0
3 years ago
F(x)=x^3+3
lawyer [7]

Answer:

  (a)   -3/4

  (b)  -0.75

  (c)  -0.75

Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

  • evaluating the function at the midpoint of the bracketing interval
  • choosing a smaller bracketing interval
  • identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

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(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

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(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

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(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

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See the attached table for function values.

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<em>Comment on bisection iteration</em>

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.

5 0
3 years ago
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Setler79 [48]

Answer:

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Step-by-step explanation:

5 0
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Vsevolod [243]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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