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SCORPION-xisa [38]
2 years ago
13

To prepare for a bake-off, Luis used 590 grams of flour each day for 3 weeks. How many kilograms did Luis use in those 3 weeks?

1 g = 0.001 kg Solve this on paper. Then check your answer on Zearn. Luis used kilograms of flour in 3 weeks.
Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
7 0

Answer: 12.39\ kg

Step-by-step explanation:

Given

Luis used 590 gm of flour each day

If he continues to use it for 3 weeks

A week has 7 days; so 3 weeks have 21 days

The flour used in 21 days

\Rightarrow 21\times 590\\\Rightarrow 12,390\ g\ \text{or}\ 12.39\ kg

Thus, 12.39\ kg of flour is used in 3 weeks

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Answer:

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Step-by-step explanation:

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3 years ago
PLS<br> Write a real world problem for the inequality 8-2x≤5.
Hatshy [7]

Step-by-step explanation:

  • 8-2x<u><</u><u> </u><u>5</u>
  • -2x<u><</u>5-8
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hope it helps.

3 0
3 years ago
A rectangle is four times as long as it is wide. If its length were diminished by 6 meters and its width were increased by 6 met
valkas [14]

Answer:

Length equals 16 and Width equals 4

Step-by-step explanation:

First let us create an equation. We can use L and W for length and width.

If the length is 4 times the width, then we end up with: L = 4W

It then says, " If its length were diminished by 6 meters and its width were increased by 6 meters, it would be a square."

Since a square has an equal length and width then we end up with:

L - 6 = W + 6

Knowing this we can just substitute the first equation into the second one leaving us with: 4W - 6 = W + 6

We then remove a W from both sides so that the right side is left with a 6, and add 6 to both sides to remove the -6 from the left one.

This leaves us with 3W = 12

W = 4, and if we put that into our first equation, L = 4W, then Length equals 16, and Width equals 4. We can check this by putting it into the 2nd equation. 16 - 6 = 4 + 6.

7 0
1 year ago
6v+12b=504<br> 2v+5b=204
ss7ja [257]

Answer:

Step-by-step explanation:

6v + 12b = 504       eq1

2v +  5b = 204        eq2

6v +  15b = 612       eq2  times 3    

0     -3b   = 504 - 612        subtraction of the two bolded eqs

         -3b  =  -108                solve for b

            b  =    36

    Another way to solve the problem

6v + 12b = 504        I would eliminate the v term by multiplying the bottom

2v +  5b = 204        equation by -3 on BOTH sides and then add the two eqs

   2v +  5b  = 204

-3(2v +  5b) = -3(204)

 -6v  -  15b  =  -612

   

6v  + 12b  =   504

-6v  -  15b  =  -612            add the like terms

(6v + (-6v)) + (12b + (-15b)  =  504 + (-612)

(6v -6v)) + (12b - 15b)  =  504 - 612)

    0       +         -3b     =    - 108            solve for b   divide both sides by -3

                           b   =  -108/-3

                             b =  36                  

use eq   2v +  5b = 204       to solve for v       and knowing b = 36

        2v +  5b = 204      b=36

        2v +  5(36)  = 204                 substract 5 times 36 from both sides

                 2v   =   204 - 180

                    v  =    24 / 2

                    v  =  12

NOW CHECK the values for b and v using the OTHER eq

       6v      +     12b      =    504

       6(12)   +   12(36)    =    504

         72    +     432      =    504

                        504      =    504           IT CHECKS

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BC<br> Round your answer to the nearest hundredth.<br> А<br> 65°<br> 6<br> B<br> ?
belka [17]

Answer:

90

Step-by-step explanation:

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