All categories

3 years ago

Prove that the sum of two odd numbers is an even number

1 answer:

5 0

Let a and b be odd number.
Because they are odd, by definition:
a = 2n + 1
b = 2m + 1
If we add them up:
a + b = 2n + 1 + 2m + 1
= 2n + 2m + 2
= 2(n + m + 2)
= 2k where k = n + m + 2

therefore a + b is always even.

You might be interested in

14. Find the coordinates of the circumcenter for ∆DEF with coordinates D(1,1) E (7,1) and F(1,5). Show your work.

Bess [88]

Hello :
the <span>coordinates </span> circumcenter for ∆DEF :
x = (1+7+1)/3
y = (1+1+5//3
x=3
y= 7/3

6 0

3 years ago

Elena wants to make a scale drawing of her bedroom using the scale 4cm to 1m. If Wall A in the drawing is 10 cm long, what is th

astra-53 [7]

Answer:

40 m

Step-by-step explanation:

6 0

3 years ago

ASAP HURRY!!!!!!!!!!!!!!!!!!!Complete the following statement. 3 ( 20 + 4 ) = a0

Lina20 [59]

Answer:

Step-by-step explanation:

3(20+4)=a0

60+12=a0

72=a0

im not quite sure what you want. I solved for a0. Plz tell me if this is correct. If its not, tell me what u need, then I will solve it for you.

5 0

3 years ago

Read 2 more answers

Princess Kate is trying on wedding dresses. Each dress is too small, fits well, or is too big. Princess Kate estimates that 40%

Tcecarenko [31]

The answer would be 35%

8 0

3 years ago

Read 2 more answers

28, 45, 12, 34, 36, 45, 19, 20

Alborosie

1) Mean of the set of data: 29.88

2) Mean absolute deviation: 10.13

3) See explanation

Step-by-step explanation:

The mean of a set of data it is calculated as

$\bar x = \frac{1}{N}\sum x_i$

where

N is the number of data in the set

$x_i$ is the value of each point in the dataset

For the set of data in this problem, we have:

$x_i =[28, 45, 12, 34, 36, 45, 19, 20]$

And the number of values is

N = 8

Therefore, we can calculate the mean:

$\bar x = \frac{1}{8}(28+ 45+ 12+ 34+ 36+ 45+ 19+ 20)=\frac{239}{8}=29.88$

The mean absolute deviation of a set of data is given by

$\delta = \frac{1}{N}\sum |x_i-\bar x|$

where

N is the number of values in the dataset

$x_i$ are the single values

$\bar x$ is the mean of the dataset

The dataset here is

$x_i =[28, 45, 12, 34, 36, 45, 19, 20]$

The mean, calculated in part 1), is

$\bar x = 29.88$

And

N = 8

Therefore the mean absolute deviation is

$\delta = \frac{1}{8}(|28-29.88|+|45-29.88|+|12-29.88|+|34-29.88|+|36-29.88|+|45-29.88|+|19-29.88|+|20-29.88|)=\frac{81}{8}=10.13$

The mean of a dataset is the sum of the single values of the dataset divided by the number of values. The mean represents the value $\bar x$ for which, if the dataset would have N values all equal to $\bar x$ , the sum of the values of the dataset would be the same as the sum of the actual values.

The mean absolute deviation for a set of data represents the average of the absolute deviations of the single points from the mean of the dataset. This quantity gives a measure of the "dispersion" of the points around the mean: in fact, the larger the mean absolute deviation is, the more the points are "spread" around the mean of the dataset. Instead, if the mean absolute deviation is small, it means that the points are closer to the mean value.

Learn more about mean and spread of a distribution:

brainly.com/question/6073431

brainly.com/question/8799684

brainly.com/question/4625002

#LearnwithBrainly

7 0

4 years ago