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Molodets [167]
3 years ago
13

If you multiply 2/3×6/10 Will the product more than 2/3 or less than 2/3

Mathematics
1 answer:
BigorU [14]3 years ago
6 0

To multiply these two fractions just multiply both numerators and both denominators.

= \frac{2}{3}*\frac{6}{10}

~Multiply

= \frac{2 * 6}{3 * 10}

~Simplify

= \frac{12}{30}

~Simplify

= \frac{6}{15}

~Simplify

= \frac{2}{5}

2/5 = 0.4

2/3 = 0.6...

0.6... > 0.4

It will be LESS then 2/3.

Best of Luck!

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Evaluate 3|-3|<br><br><br> -6<br> 6<br> -9<br> 9
evablogger [386]

Answer:

9

Step-by-step explanation:

The absolute value of -3 is |-3|, which in turn is 3.  Thus we have

3(3), or 9.  The fourth answer choice is the correct one.

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3 years ago
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S_A_V [24]
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8 0
3 years ago
PLZ HELP !! Which of the points (s, t) is not one of the vertices of the shaded region of the
stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

  • A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

  • B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0  True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

  • C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4  True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

  • D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10)  is not one of the vertices of the shaded region of the  set of inequalities.

3 0
3 years ago
ANSWER QUICK!!!
Ilia_Sergeevich [38]

Answer:

87.5%

Step-by-step explanation:

5 0
3 years ago
25 POINTS
Semenov [28]

If the slope of AB = CD and BC = AD it's a parallelogram:

Slope of AB = 6+1 / -9+5 = -7/4

CD = -2-5 / 3+1 = -74

These are equal.

BC = 5-6 / -1 +9 = -1/8

AD = -2 +1 / 3+5 = -1/8

These are also equal so it is a parallelogram.

Now to find if the diagonals are perpendicular find the slope of the perpensicular points:

AC = 5 +1 / -1 +5 = 6/4 = 3/2

BD = 6+2 / -9 -3 = 8/-12 = -2/3

Because BD is the reciprocal of AC, this means they are perpendicular.

And because AB is not perpendicular to AD ( AB and AD are not reciprocals) it is a rhombus.

5 0
3 years ago
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