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3 years ago

A candy store called "Sugar" built a giant hollow sugar

Mathematics

1 answer:

kirill [66]3 years ago

8 0

Answer:

27‬ cubic ft

Step-by-step explanation:

The formula for volume is Base * Height * Width;

and the formula for area is Base * Height.

This problem mentions the structure is a cube and therefore it is assumed that every wall has the same area. Since there are 6 sides to a cube you divide the total amount of ft which make up this cube to know the area to each wall.

54 ft / 6 walls = 9 ft per wall

With the area of each wall you can find the base and height:

base * height = area

base = height ..... b*h ..... b*b=area ..... b^2 = area ... b = sqrt(area)

b = sqrt(9) = 3

base = 3ft

height = 3ft

since: base=height=width

width = 3ft

volume = 3 * 3 * 3 = 3^3 = 27 ft^3

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Please answer ASAP I will give you five stars

Nataliya [291]

Known :

r = 6

h = 8

Asked :

V = ...?

Answer :

V = ⅓πr²h

= ⅓ × 3.14 × 6² × 8

= ⅓ × 3.14 × 36 × 8

= 3.14 × 12 × 8

= 301.44 units²

= 300 units² (rounded)

So, the volume of the cone is 300 units²

Hope it helpful and useful :)

3 0

3 years ago

Alan buys a basket of apples on sale for $7 before tax. The sales tax is 12.5%. What is the

shtirl [24]

7.87 is what i got :) good luck!!

5 0

3 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

3 years ago

Read 2 more answers

Sector problem please help

hammer [34]

Answer:

The answer is (π/4)*r

Step-by-step explanation:

Formula length of arc when the angle given is in radian as the case given

s = r*θ

s = arc length (in radians)

r = radius

θ = central angle in radians

But when the angle given is in degrees the length is expressed as

s= 2πr*(θ/360)

7 0

3 years ago

A firm has the following fixed proportion production function q = min(k, 2l). a. Find the firms long-run total, average, and mar

Yuri [45]

Answer:

I think its right

Step-by-step explanation:

a) In the long run, we have, 5k=10 and k=2l Thus, C=2l+3l= 5l=0.5q Thus, AC=5l/10l =0.5 MC=0.5 b) In the short run, k=10 Q=min(50,10l) If l<5, q=10l. C=10+3l= 10+0.3q Thus, AC=10/q + 0.3 If l>5, q=50. C= 10+3l AC= (10+3l)/50 If q>50, then MC...

3 0

2 years ago