Find the vertex of y=-x^2+6x-12

1 answer:

8 0

You find the x coordinates using x = -b/2a = -6/2(-1) = 3

Substitute 3 in the equation and find y

y = -(3^2) + 6(3) - 12 = -9 + 18 - 12 = -3

Vertex (3,-3)

You might be interested in

-4=b/2 a)-8 b)-2 c)2 D)8

Kitty [74]

Answer : A {-8}

-4 = b/2

-4 *2 = b

-8 = b

7 0

3 years ago

Solve D 41=12d-7 zhcduhdudebiscbihbihb

Daniel [21]

Answer:

Step-by-step explanation:

12d - 7 = 41

12d = 48

d = 4

5 0

3 years ago

17=14 3/4+ 1/6+ missing number

Lostsunrise [7]

1. 1/3 for 14 3/4+ 1/6= 15 6/12 now 17 -15 6/12 =1 6/12 which is the same as 1 1/3

3 0

3 years ago

Rewrite the equation in Ax+By=C form. Use integers A, B, and C. y+5=5(x-3)

Kaylis [27]

$y+5=5(x-3)\\ y+5=5x-15\\ 5x-y=20$

4 0

3 years ago

Read 2 more answers

Determine the end behavior of the function: f(x)= -3x*4

g100num [7]

F(x)=-3x*4 = 6x^2 +C

8 0

3 years ago