Find the vertex of y=-x^2+6x-12

1 answer:

8 0

You find the x coordinates using x = -b/2a = -6/2(-1) = 3

Substitute 3 in the equation and find y

y = -(3^2) + 6(3) - 12 = -9 + 18 - 12 = -3

Vertex (3,-3)

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