Question

Find the vertex of y=-x^2+6x-12

Answer 1

You find the x coordinates using x = -b/2a  = -6/2(-1) = 3

Substitute 3 in the equation and find y

y = -(3^2) + 6(3) - 12 = -9 + 18 - 12 = -3

Vertex (3,-3)