Given:
15 students
2 students must be chosen.
No repetition, no order
This is a combinations problem. We use this formula: n! / (n-r)!(r!)
n = 15 ; r = 2
15! / (15-2)!(r!) ⇒ 15! / 13! * 2! = 105
Answer:
C. Mean
Step-by-step explanation:
We have been given that obtaining a measure of intelligence from a group of college students would likely yield a somewhat normal distribution (that is, there shouldn't be any extreme outliers).
We know that median is best measure of central tendency with extreme outliers, while mean is the best measure of central tendency when the data is normally distributed.
Mode is used when data are measured in a nominal scale.
Since the measure of intelligence from a group of college students yield a somewhat normal distribution, therefore, mean will be the best measure of central tendency.
Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
Answer:
b) .474
Step-by-step explanation:
If 62% go to a four-year college, that means that those who don't represent 38% of the high-school graduates.
You pick up someone who is NOT going to a four-year college (so, he's among the 38%)... what's the chance he's in the 18% of the whole high-school graduates population that found a job?
To calculate that probability, we have to divide 18% by 38%.
P = 18% / 38% = 0.4736, so 0.474
Since we are sure he doesn't go to a four-year college, there's 47.4% of chances he finds a job.
