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Dahasolnce [82]
3 years ago
7

A rectangular prism has a length of 1 2 in, a width of 2 in, and a height of 3 1 2 in. (a) How many cubes with side lengths of 1

2 in. will fit into the prism? Show your work or explain your thinking! (b) What is the volume of this prism? Write your answer as a simplified mixed number. Show ALL of your work!
Someone please help will give brainliest (50 pts)
Mathematics
2 answers:
erma4kov [3.2K]3 years ago
4 0
V of rectangular prism = l * w * h = 12 * 2 * 312 = 7,488 in³
V of one cube with side lengths 12 = l * w * h = 12 * 12 * 12 = 1,728 in³

Divide the volume of rectangular prism by the volume of the cube.

7488 / 1728 = 13 / 3 or 4.3. . .


mixas84 [53]3 years ago
4 0
V of rectangular prism = l * w * h = 12 * 2 * 312 = 7,488 in³V of one cube with side lengths 12 = l * w * h = 12 * 12 * 12 = 1,728 in³
Divide the volume of rectangular prism by the volume of the cube.
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We'll use PEMDAS which stands for

P = parenthesis

E = exponents

M = multiplication

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It tells us the order in how to evaluate math expressions. We start with parenthesis, then move to exponents, etc until we get to subtraction as the last step.

We have parenthesis so we focus on whats inside it. We evaluate 2^0 to get 1. Any nonzero number to the exponent 0 is always 1. In other words, x^0 = 1 where x is nonzero.

So 3(2^0) turns into 3(1) or 3*1

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3 years ago
The mad scientist will need one-third of the eyeball how many eyeball is that
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Answer:

1/3

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The mad scientist needs one-third or 1/3 of the eyeball.

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Wendy is creating a large soup based on a recipe. Her recipe calls for of a pint of milk, but she only has of a pint of milk, so
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3 years ago
The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9
mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em>h(t)<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>h(t) = 3 +90\cdot t -16\cdot t^{2}<em>, where </em>t<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

3+90\cdot t -16\cdot t^{2} = 84

16\cdot t^{2}-90\cdot t +81 = 0 (1)

By Quadratic Formula:

t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}

t_{1} = 4.5\,s, t_{2} = 1.125\,s

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0
3 years ago
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