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Vitek1552 [10]
3 years ago
14

Between 11 P.M. and 8:36 A.M.​, the water level in a swimming pool decreased by 8 25 in. Assuming that the water level decreased

at a constant​ rate, how much did the water level drop each​ hour?
Mathematics
1 answer:
Eva8 [605]3 years ago
6 0

Answer:

0.8594 in/hr

Step-by-step explanation:

Decreased in the water level is 8.25 in.

Time 11 P.M. and 8:36 A.M.  is 9 hr 36 min = 9.6 hr.

The rate of decreasing water level is constant.

So, \text{Rate}=\frac{\text{Level decreased}}{\text{Time taken}}

\Rightarrow \text{Rate}=\frac{8.25}{9.6}=0.8594 in/hr.

Hence, the water level drop at the rate of 0.8594 in/hr.

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let X be number of students

and y be total cost

when 30 students (30,X)where at the gym it's costs 200 (y,200)

=that is (X,y)=(30,200)

when 70 students where at the gym

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now we find the slope

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= 2.5=3

now

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we need to find the value of b

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X=30,200

200=2(30)+b

re-arrange

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hope it's helpful

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3 years ago
Solve for t<br><br> - 7/4 = 2/5 (t)<br><br> t=
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