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Vitek1552 [10]
3 years ago
14

Between 11 P.M. and 8:36 A.M.​, the water level in a swimming pool decreased by 8 25 in. Assuming that the water level decreased

at a constant​ rate, how much did the water level drop each​ hour?
Mathematics
1 answer:
Eva8 [605]3 years ago
6 0

Answer:

0.8594 in/hr

Step-by-step explanation:

Decreased in the water level is 8.25 in.

Time 11 P.M. and 8:36 A.M.  is 9 hr 36 min = 9.6 hr.

The rate of decreasing water level is constant.

So, \text{Rate}=\frac{\text{Level decreased}}{\text{Time taken}}

\Rightarrow \text{Rate}=\frac{8.25}{9.6}=0.8594 in/hr.

Hence, the water level drop at the rate of 0.8594 in/hr.

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Step-by-step explanation:

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the slope of the original line is -2/5.

as in every line equation, the slope is the factor of x. and it expresses the ratio y/x indicating the amount of units y is changing, when x changes a certain amount of units (e.g. when going from one point on the line to another).

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the equation for the perpendicular line looks like

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