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3 years ago

Solve for w 6w + 4w - 9 + 6 = 9w - 7+ 6

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

4 0

Answer:

w = 2

Step-by-step explanation:

6w + 4w - 9 + 6 = 9w - 7+ 6

6w + 4w - 9w = - 7 + 6 + 9 - 6

w = 2

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Help will give brainliest!!!!!!

sashaice [31]

Answer:

2.5

type A/B

Step-by-step explanation:

10/2.5=4

15/6=2.5

18/7.2=2.5

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3 years ago

...I don’t understand umm can anyone help me smh-

Anna007 [38]

Answer:

{Rounded to the nearest Hundredths place}

1) Mercury= 170.55
2) Venus= 277.86
3) Earth= 389.62
4) Mars= 401.29

Explanation:

Mercury: 3.3022 x 10^19= 170.549894825 which rounds to 170.55

Earth: 5.9722 x 10^24= 389.618945662 which rounds to 389.62

Venus: 4.8675 x 10^21= 277.855972801 which rounds to 277.86

Mars: 6.4185 x 10^23= 401.287714067 which rounds to 401.29

•So smallest to largest would be• 170.55, 277.86, 389.62, and 401.29

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3 years ago

The number of points scored in a basketball game by Slim Dunkin is shown in the table at right:

brilliants [131]

I think the answer would be d in my opinion

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3 years ago

(6- -6 + 5.3) / -2.25

STALIN [3.7K]

Answer:

346 / 45

Step-by-step explanation:

6 + 6 + 5.3

----

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3 years ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve