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3 years ago

How can you tell if ordered pairs are a function or not

Mathematics

2 answers:

ra1l [238]3 years ago

7 0

Answer:

You can tell if the x repeats

Step-by-step explanation:

dimulka [17.4K]3 years ago

5 0

Answer:

Step-by-step explanation:

How do you figure out if a relation is a function? You could set up the relation as a table of ordered pairs. Then, test to see if each element in the domain is matched with exactly one element in the range. If so, you have a function!

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Which of the following is not a subset of {1, 2, 3}? {0} {1, 2, 3} Ø

Butoxors [25]

Answer:

{0}

Step-by-step explanation:

{0} is not because 0 is not an element of set {1, 2, 3}

The null set is a subset of every set, so Ø is.

A set is a subset of itself.

6 0

3 years ago

Solve each equation by taking square roots 9v^2=25

lisov135 [29]

9v^2=25
v^2 = 25/9
v^2 = (5/3)^2
v = + 5/3 and v = -5/3

hope it helps

3 0

3 years ago

I will mark you brainliest! The value of a car decreases by 1/6 every year. What type or function represents this pattern?

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

When the value of something decreases by a certain factor every unit of time, instead of by a set constant, then this is called exponential decay. When the rate is constant, this is called linear decay. Hope this helps!

3 0

3 years ago

Complete the factoring, 5x^2 - 40x = 5x( ) HELP ASAP PLS!

Aleksandr-060686 [28]

Answer:

$5x(x-8)$

Step-by-step explanation:

Factor $5x$ out of $5x^{2} -40x$

8 0

3 years ago

a water balloon is tossed into the air with an upward velocity of 25 ft/s its height h(t) in ft after t seconds is given by the

Montano1993 [528]

When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula

for
0=ax²+bx+c
$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$

so for
0=-16t²+25t+3
a=-16
b=25
c=3
so

$x=\frac{-25+/-\sqrt{25^2-4(-16)(3)}}{2(-16)}$
$x=\frac{-25+/-\frac{625+192}}{-32}$
$x=\frac{-25+/-\frac{817}}{-32}$
it has to be a positive time

so it will hit the ground after $\frac{25+\sqrt{817}}{32}$ seconds

4 0

3 years ago