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Kryger [21]
3 years ago
13

Find the missing measures

Mathematics
1 answer:
Yanka [14]3 years ago
7 0
The middle right is 145-90, so 55°. I'm not sure about the others
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What is the value of 3 in 345,268.19
astra-53 [7]
3 is 300,000 in 345,268.19
7 0
2 years ago
Simplify the expression 6x+12y+5+2y+8 what is the coefficient of y and what is the constant
frez [133]
We want to find the coeficient of the y terms when added together so find all the y terms

+12y and +2y
we add them together
12y+2y=(12+2)y=(14)y=14y
coeficient is 14


the constant is the number that is set already or the number that doesn't have it multiplied by a placeholder exg. 4 is a constnat but 4x is not so find the constants
+5 and +8
we add
5+8=13
the constant is 13


y coeficient=14
constant=14
5 0
3 years ago
Read 2 more answers
What is the combined lenght of all buttons longer than 1 inch?
HACTEHA [7]

Answer:

2 12 1/2 inches

Step-by-step explanation:

1: 1 1/4 + 1 1/4

2: 1+1 = 2; 1/4 + 1/4 = 2/4

3:  2 2/4

Answer:  2 2/4

<em><u>Hope this helps.</u></em>

7 0
3 years ago
In an ore, 9.8% of its total weight is metal. How many pounds of metal are in 1,950 lb of ore?
Fudgin [204]

Answer

Find out the  how many pounds of metal are in 1,950 lb of ore .

To proof

let us assume that the pounds of metal are in 1,950 lb of ore be x .

As given

In an ore, 9.8% of its total weight is metal.

ore weight = 1,950 lb

9.8% is written in the decimal form

= \frac{9.8}{100}

= 0.098

Than the equation becomes

x = 0.098 × 1950

x = 191.1 pounds

Therefore the 191.1 pounds of metal are in 1,950 lb of ore .

Hence proved



5 0
3 years ago
You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,
Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3

The coordinates of the fourth vertex is D(4,-3)

3 0
3 years ago
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