Log₂(6x) - log₂(√x) = 2
log₂[6x/√x] = 2, let's rewrite it in terms of exponent:
(remember : ㏒₂(x) = a (in exponential form) → x = 2ᵃ
6x/√x = 2²
6x/√x = 4, square both sides:
36x²/x = 16 .Simplify:
36x = 16 and x = 16/36 . So x = 4/9
Answer:
The given set of equation are: x+ (-45) ≤ 35 , x - (-45) ≥ 35
For the given equality to be true, x ≤ 35
Step-by-step explanation:
Here, given the first number = x
Second number = -45
Now, Sum of x and - 45 is at most 35.
⇒ x+ (-45) ≤ 35
Also, The difference of x and -45 is at least 35.
⇒ x - (-45) ≥ 35
Now, simplifying the given set of equations:
x - 45 ≤ 35 ⇒ -x - (-45) > - 35 ( as 3 < 4 ⇒ -3 > -4)
or, -x + 45 > - 35
and second equation is x + 45 ≥ 35
Now, solving both the equations by not taking sign of inequality in to the consideration, we get
x - 45 = 35
x + 45 = 35
Adding both equations,we get: ⇒ 2x = 70
or x = 35
Hence for the given equality to be true, x ≤ 35
Answer:
116
Step-by-step explanation:
Total degrees in a pentagon: 540
Therefore, x + x + 100 + 101 + 107 = 540
2x + 308 = 540
2x = 232
x = 116
