Answer:
Addition
Step-by-step explanation:
Since you are trying to make x the subject, you need to "get rid" of the -2. So, because it is a negative number, you add 2 to make it 0, which is added to both sides, making x = 7.
Hope this helps!
Answer:
a. (15, 15)
Step-by-step explanation:
We start with those two equations:
1) a - 1.2b = -3
2) 0.2b + 0.6a = 12
We'll begin by modifying equation #1 to isolate a:
a = -3 + 1.2b
Then we'll use this value for a in the second equation:
0.2b + 0.6 (-3 + 1.2b) = 12
0.2b - 1.8 + 0.72b = 12
0.92b = 13.8
b = 15
Then we'll place that value of b in the first equation to find a:
a - 1.2 (15) = -3
a - 18 = -3
a = 15
The surface area of the given right angled triangular prism is 60 square centimeters (
).
Step-by-step explanation:
The given is,
Right angled triangular prism
Step:1
Surface area of triangular prism,
.........(1)
Step:2
Area of Triangular face,
![= \frac{1}{2}(base)(height)](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B2%7D%28base%29%28height%29)
![= \frac{1}{2} (3)(4)](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B2%7D%20%283%29%284%29)
![=\frac{1}{2} (12)](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%20%2812%29)
In right angled triangular have two triangular faces,
![= (2)(6)](https://tex.z-dn.net/?f=%3D%20%282%29%286%29)
![=12 cm^{2}](https://tex.z-dn.net/?f=%3D12%20cm%5E%7B2%7D)
Step:3
Area of sloping rectangular face,
![=lb](https://tex.z-dn.net/?f=%3Dlb)
![=(4)(5)](https://tex.z-dn.net/?f=%3D%284%29%285%29)
![=20 cm^{2}](https://tex.z-dn.net/?f=%3D20%20cm%5E%7B2%7D)
Step:4
Area of back side
![=12cm^{2}](https://tex.z-dn.net/?f=%3D12cm%5E%7B2%7D)
Step:5
Area of bottom side ![=(4)(4)](https://tex.z-dn.net/?f=%3D%284%29%284%29)
From the equation (1),
![=12+20+12+16](https://tex.z-dn.net/?f=%3D12%2B20%2B12%2B16)
![= 60cm^{2}](https://tex.z-dn.net/?f=%3D%2060cm%5E%7B2%7D)
Result:
The surface area of the given right angled triangular prism is 60 square centimeters (
).