Answer:
<u>Point C at (-18/7)</u>
Step-by-step explanation:
Point A is at -6 and point B is at 2.
So, the distance between A and B = 2 - (-6) = 8
point C on the directed line segment from A to B on a number line such that the segment is partitioned in a ratio of 3:4.
Let the distance AC = x
∴ BC = 8 - x
AC : CB = 3 : 4
∴
Using cross multiplication
3 (8-x) = 4x
24 - 3x = 4x
24 = 7x
x = 24/7
So, Point C = -6 + 24/7 = -18/7
Point C at (-18/7)
Alright sure:
Q5: ∠3
Q6: ∠1
Q7: ∠2
Q8: x = 25
Q9: x = 63
For Questions 8 and 9 what I did was find out the supplementary angle adjacent to the exterior angle.
8: 180° in a supp. angle. So 180-105 = 75. To make a triangle it has to be 180°. So 180 - 75-80 = 25 So x=25
9: 180° in a supp. angle. So 180-135 = 45. To make a triangle it has to be 180°. So 180 - 45-72 = 63. So x=63
Let me know if you don't understand that. If you don't get it I'll explain it further for you.
