
is the answer of the question
Answer: 9/4
Step-by-step explanation: Think of
as
.
Now, we can change 4⁻¹ to 4¹ by moving it to the denominator and
we can change 9⁻¹ to 9¹ by moving it to the numerator.
So we have 9¹/4¹ which simplifies to 9/4.
Answer:
0.0114
Step-by-step explanation:
(a) What is the probability of a fatal accident over a lifetime?
Suppose A be the event of a fatal accident occurring in a single trip.
Given that:
P(1 single auto trip in the United States result in a fatality) = P(A)
Then;
P(A) = 1/4011000
P(A) = 2.493 × 10⁻⁷
Now;
P(1 single auto trip in the United States NOT resulting in a fatality) is:
P(
) = 1 - P(A)
P(
) = 1 - 2.493 × 10⁻⁷
P(
) = 0.9999997507
However, P(fatal accident over a lifetime) = P(at least 1 fatal accident in lifetime i.e. 46000 trips)
= 1 - P(NO fatal accidents in 46000 trips)
Similarly,
P(No fatal accidents over a lifetime) = P(No fatal accident in the 46000 trips) = P(No fatality on the 1st trip and No fatality on the 2nd trip ... and no fatality on the 45999 trip and no fatality on the 46000 trip)
= ![[P(\overline A)] ^{46000} \ \ \ (since \ trips \ are \ independent \ events)](https://tex.z-dn.net/?f=%5BP%28%5Coverline%20A%29%5D%20%5E%7B46000%7D%20%20%5C%20%5C%20%5C%20%20%28since%20%5C%20%20trips%20%5C%20are%20%5C%20independent%20%5C%20events%29)
= ![[0.9999997507]^{46000}](https://tex.z-dn.net/?f=%5B0.9999997507%5D%5E%7B46000%7D)
= 0.9885977032
Finally;
P(fatal accident over a lifetime) = 1 - 0.9885977032
P(fatal accident over a lifetime) = 0.0114022968
P(fatal accident over a lifetime) ≅ 0.0114
Europe. And just so you know this should have been under a different topic.