Answer: 3sqrt(2)
Step-by-step explanation:
d = sqrt[(3-0)^2 + (4-1)^2]
d = sqrt[9+9]
d = sqrt(18) = 3sqrt(2)
Answer:
Step-by-step explanation:
Report by Oopsydaisy 17.06.2016
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Answer;
C) The second arc should be centered at C.
Assuming the goal is to construct a line parallel to AB that passes through given point C.
-Draw a line through C and across AB at an angle creating D.
- With the compass width about half of DC, and center D, draw the first arc to cross b
Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
I believe it would be 13p im not for sure though
0.08 / 0.5216
Answer: 0.15337423312
