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2 years ago

Pls tell me the answer with the work shown

Mathematics

1 answer:

shepuryov [24]2 years ago

4 0

Answer:

plug in the numbers for radius, and know your formulas. a diameter is 2 times a radius so

Pi or 3.14 times D is the same as 2 times pi times radius.

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WILL MARK BRAINIEST!!!

Zarrin [17]

R^2/2(pi/180*D-sin(D)) is the formula so 6^2/2(pi/180*120-sin(120)) is the problem which comes to about 22cm^2

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2 years ago

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Please help me with this

tankabanditka [31]

I think this is what I found

3 0

2 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

<em>Hence the projection of b unto a is expressed as </em> $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$ <em></em>

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3 years ago

Which rule describes the composition of transformations that maps figure ABCDE to figure A”B”C”D”E?

Mrrafil [7]

The last selection should be your answer

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3 years ago

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11x -20y=28 3x+4y =36

jekas [21]

Answer: X is equal to 8 and Y is equal to 3

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2 years ago

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