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3 years ago

11

Angle 1 is supplementary to angle 2

1 answer:

Pepsi [2]3 years ago

7 0

9514 1404 393

Answer:

congruent

Step-by-step explanation:

Angles supplementary to the same angle are congruent.

__

Here, angles 1 and 3 are both supplementary to angle 2, so ...

angle 1 and angle 3 are congruent

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Can you answer and explain please

nalin [4]

Answer what exactly?

8 0

2 years ago

What is the length of a hypotenuse of a triangle if each of its legs is 4 units

azamat

Answer:

$\boxed{c = 5.7 units}$

Step-by-step explanation:

<u><em>Using Pythagorean Theorem:</em></u>

=> $c^2 = a^2+b^2$

Where c is hypotenuse, a is base and b is perpendicular and ( a, b = 4)

=> $c^2 = 4^2+4^2$

=> $c^2 = 16+16$

=> $c^2 = 32$

Taking sqrt on both sides

=> c = 5.7 units

8 0

2 years ago

Read 2 more answers

Differentiate with respect to X <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7Bcos2x%7D%7B1%20%2Bsin2x%20%7D%20

Mice21 [21]

Power and chain rule (where the power rule kicks in because $\sqrt x=x^{1/2}$ ):

$\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'$

Simplify the leading term as

$\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}$

Quotient rule:

$\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}$

Chain rule:

$(\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)$

$(1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)$

Put everything together and simplify:

$\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}$

$=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}$

$=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}$

5 0

2 years ago

How do you simplify radical 32

EleoNora [17]

$\sqrt{32}= \sqrt{16*2}= \sqrt{16}* \sqrt{2}=4 \sqrt{2}$

4 0

3 years ago

A number is increased by 54. The sum is then divided by 9. The result is 21. Write an equation to represent the description abov

Andrew [12]

54 devided by 9 will equal to 21

5 0

2 years ago

Read 2 more answers