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Liula [17]
3 years ago
10

Help Please

Mathematics
2 answers:
lesya692 [45]3 years ago
8 0

Paris Nights sweater: $60

Markup: 35% of $60

35/100=x/60

Cross multiply

2100 divide by 100 is 21

$60 + $21 = $81

The answer is $81

Sav [38]3 years ago
6 0
$60×.35 equals= $21 mark up
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Please help! I don’t have much to offer except the crown icon thing and 15 points.
Goshia [24]
<h2><u>SOLUTION</u><u>:</u></h2>

x/9>12

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This is your answer

8 0
3 years ago
An aircraft emergency locator transmitter (ELT) is a device designed to transmit a signal in the case of a crash. The ACME Manuf
iren [92.7K]

Answer:

a) P(ACME) = 0.7

b) P(ACME/D) = 0.5976

Step-by-step explanation:

Taking into account that ACME manufacturing company makes 70% of the ELTs, if a locator is randomly selected from the general population, the probability that it was made by ACME manufacturing Company is 0.7. So:

P(ACME) = 0.7

Then, the probability P(ACME/D) that a randomly selected locator was made by ACME given that the locator is defective is calculated as:

P(ACME/D) = P(ACME∩D)/P(D)

Where the probability that a locator is defective is:

P(D) = P(ACME∩D) + P(B. BUNNY∩D) + P(W. E. COYOTE∩D)

So, the probability P(ACME∩D) that a locator was made by ACME and is defective is:

P(ACME∩D) = 0.7*0.035 = 0.0245

Because 0.035 is the rate of defects in ACME

At the same way, P(B. BUNNY∩D) and P(W. E. COYOTE∩D) are equal to:

P(B. BUNNY∩D) = 0.25*0.05 = 0.0125

P(W. E. COYOTE∩D) = 0.05*0.08 = 0.004

Finally, P(D) and P(ACME/D) is equal to:

P(D) = 0.0245 + 0.0125 + 0.004 = 0.041

P(ACME/D) = 0.0245/0.041 = 0.5976

5 0
3 years ago
What is 20% of 25? pls help worth 25 points
Dovator [93]

Answer:

5.

Step-by-step explanation:

Use a proportion.

7 0
3 years ago
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Inessa05 [86]

Answer:

D

Step-by-step explanation:

Because I know

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3 years ago
Adar, Chi, and Melissa each left the party by themselves. In how many different orders can they leave?
Leona [35]
The answer is A they can only be in different orders
4 0
3 years ago
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