Thats what I got. I hope it helps :)
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer:
Rule: If working with an inequality and you either mult. or div. by a negative number, you must reverse the direction of the inequality symbol.
Step-by-step explanation:
Your job here is to simplify 9t-4>32, in which the variable (t) is already positive. Here you do NOT switch signs or reverse the direction of the inequality symbol. Adding 4 to both sides, we get 9t > 36, or t > 4.
If, however, you had -9t-4>32 to work with, the situation would be different because t in this inequality is negative. Adding 4 to both sides results in:
-9t > 36. To solve for t, we must divide both sides by -9 AND reverse the direction of the inequality symbol:
t < -4.
Rule: If working with an inequality and you either mult. or div. by a negative number, you must reverse the direction of the inequality symbol.
97 Rounded to the nearest tenth would be 100
Answer:
Scientists Could not agree on a standard
