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polet [3.4K]
3 years ago
11

Please please help me!!!!!

Mathematics
1 answer:
Tamiku [17]3 years ago
6 0
Your just multiplying 7 and 10, so your answer is gonna be B.
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A package states that there are 60 calories in 12 crackers
kvv77 [185]

Answer: 5 calories = 1 cracker

Step-by-step explanation:

60:12 = 5:1

60 calories and 12 crackers = 5 calories and 1 cracker

7 0
3 years ago
What is the final amount if 931 is decreased by 1% followed by a 1% increase?
earnstyle [38]

Answer:

930.91

Step-by-step explanation:

931 x 99% = 921.69

921.69 x 101% = 930.9069

8 0
3 years ago
Read 2 more answers
Please help with the question,
castortr0y [4]
The correct answer is x^2-2x+2=0

 The explanation is shown below:

 1. To solve the problem shown in the figure above, you must apply the following proccedure:

 2. You have that the roots of the quadratic equation shown in the figure attached in the problem are:

  x=-1±i

 3.  Then, you know the quadratic formula to solve quadratic equations, which is:

 (-b±√(b^2-4ac))/2a

 4. You can see in the figure that a=1 and c=2; then, by analizing this, you can conclude that the coefficient b is:

 b=-2

 5. Therefore, you can conclude tha the quadratic equation is:

 x^2-2x+2=0

 6. If you want to verify it, apply the quadratic formula to the quadratic equation shown above and you will obtain the roots shown in the figure.
8 0
3 years ago
Read 2 more answers
Help me answer this thanks
patriot [66]
The first fourth and sixth would be the answer
3 0
4 years ago
A cyclist rides 225 m each minute.About how long does it take to ride 15km? Show all fo your work
Elan Coil [88]
Speed = 225 metres per minute

Distance = 15 km = 15,000 metres

---------------------------------------------------

s=d/t

ts=d

Therefore: t=d/s

--------------------------------------------------

Time = Distance / Speed

Time = (15,000 metres) / (225 metres per minute)

--------------------------------------------------

Let's work it out:

Time=\frac { 15,000\quad metres }{ \frac { 225\quad metres }{ 1\quad minute\left( s \right)  }  } \\ \\ =\frac { 15,000\quad metres }{ 1 } \cdot \frac { 1\quad minute\left( s \right)  }{ 225\quad metres } \\ \\ =\frac { 15,000 }{ 225 } minutes

\\ \\ =\frac { 200 }{ 3 } minutes\\ \\ \frac { 200 }{ 3 } minutes\quad =\quad 66\quad minutes,\quad 40\quad seconds
6 0
4 years ago
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