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3 years ago

X is less than or equal to-86

Mathematics

1 answer:

ra1l [238]3 years ago

4 0

Answer:

x≤-86

Step-by-step explanation:

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-2/3,0.6,3/4,-7/4,0,3 from least to greatest

Alja [10]

Answer:

-7/4 < -2/3 < 0 < 0.6 < 3/4 < 3

Step-by-step explanation:

7 0

3 years ago

Find the value of x. Then find the measure of each labeled angle.<br> (x-52)<br> *°=0°

Viefleur [7K]

X=52
x-52=0
+52 both sides
x=52

7 0

3 years ago

PLZ HELP ME IM desperate!!!!<br> When writing a rebuttal, what is the exact phrasing we use?

vazorg [7]

1) Always be polite and professional.

2) Specifically address the points that you disagree with.

3) Provide Evidence.

4) Close with a brief summary of your rebuttal.

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2 years ago

Read 2 more answers

The table lists the number of male and female students at Lakeside High School. What is the probability of selecting a female st

Ronch [10]

Answer:

50 percent

Step-by-step explanation:

7 0

3 years ago

Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation

just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation $v(t)= 6t^2-18t+12$ . We are asked to find the distance that the particle will travel in its first 2 seconds.

$s(t)=\int |v(t)|dt$

$s(t)=\int\limits^2_0 |6t^2-18t+12|dt$

Now, we will eliminate the absolute value sign as:

$s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt$

$s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1$

$s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1$

$s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))$

$s(2)=2-9+12-(0)-16+36-24-(-2+9-12)$

$s(2)=5-(0)-4-(-5)$

$s(2)=5-4+5$

$s(2)=6$

Therefore, the particle will travel 6 feet in first 2 seconds.

7 0

3 years ago