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Nadusha1986 [10]
3 years ago
10

Need help it seems so simple but i dont know what it is

Mathematics
2 answers:
Kipish [7]3 years ago
6 0
When a point is reflected is reflected over the y-axis, the coordinates change from (x, y) to (-x, y). So the coordinates (-3, 5) would become (3, 5).
wel3 years ago
4 0
3,5 ?
Hope this helps!
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A recipe for a smoothie calls for 0.75 pound of strawberries. If Kerry has 31.5 pounds of strawberries, how many batches of the
vodomira [7]

42 batches. 31.5 divided by .75 = 42.

5 0
2 years ago
Identify the expression equivalent to 4x + x + 7) - 2x+8 - 4 by substituting x= 1 and x = 2. А. 6x + 11 B. 3(x+7) C. 2(3x + 16)
Alex

Answer:

4x + x + 7) - 2x+8 - 4 by substituting x= 1 and x = 2. А. 6x + 11 B. 3(x+7) C. 2(3x + 16) D. 3x + 16

Step-by-step explanation:

4 0
2 years ago
5pts and the person who has the correct answer gets brainliest​
Tanzania [10]

Answer:

4

Step-by-step explanation:

The one that weighs the less is 80

<u><em>Pls give brainlest.</em></u>

6 0
2 years ago
Read 2 more answers
Simplify the following Questions. (IMPORTANT NOTE!!! #'s 2 AND 7 MUST BE IN SCIENTIFIC NOTATION!!!!!) 1.) (x)²(2xy³)^5 2.) (4x10
poizon [28]

Answer:

Step-by-step explanation:

Hint :

(a*b)^{m}= a^{m}b^{m}\\\\\\(a^{m})^{n}=a^{mn}\\\\\\a^{m}*a^{n}=a^{m+n}\\

1)x^{2}(2xy^{3})^{5}=x^{2}*2^{5}*x^{5}*(y^{3})^{5}\\\\\\=x^{2}*2^{5}*x^{5}*y^{3*5}\\\\=x^{2}*2^{5}*x^{5}*y^{15}\\\\=2^{5}*x^{2+5}*y^{15}\\\\=2^{5}x^{7}y^{15}

2) (4x10^{8})^{2}=4^{2}*x^{2}*(10^{8})^{2}\\\\=16*x^{2}*10^{8*2}\\\\=1.6*10*x^{2}*10^{16}\\\\=1.6x^{2}*10^{16+1}\\\\=1.6x^{2}10^{17}

3)(-h^{4})^{5}=(-h)^{4*5}=-h^{20}\\\\\4)(3xy^{3})^{2}(xy)^{6}=3^{2}x^{2}(y^{3})^{2}x^{6}y^{6}\\\\=9x^{2}y^{3*2}x^{6}y^{6}\\\\\\=9x^{2}y^{6}x^{6}y^{6}\\\\=9x^{2+6}y^{6+6}\\\\=9x^{8}y{12}\\\\\\

5) (p^{9})^{-2}=p^{9*-2}=p^{-18}\\\\\\6)(5k^{2})^{3}=5^{3}(k^{2})^{3}=625k^{6}\\\\7)(7x10^{5})^{2}=7^{2}x^{2}(10^{5})^{2}\\\\=49x^{2}10^{5*2}\\\\=4.9*10^{1}x^{2}10^{10}\\\\=4.9x^{2}10^{10+1}\\\\=4.9x^{2}10^{11}

8)x^{3}(-x^{3}y)^{2}=x^{3}*(-x^3})^{2}y^{2}\\\\\\=x^{3}*(-1)^{2}*x^{2*3}y^{2}\\\\=x^{3}*1*x^{6}y^{2}=x^{3+6}y^{2}\\\\=x^{9}y^{2}\\\\\\9)w^{5}(w^{2})^{-4}=w^{5}w^{2*-4}\\\\=w^{5}w^{-8}\\\\=w^{5-8}=w^{-3}\\\\=\frac{1}{w^{3}}\\\\\\10) (2x^{5})^{4}=2^{4}x^{5*4}\\\\=2^{4}x^{20}\\\\=16x^{20}

5 0
3 years ago
A hemispherical tank is filled with water and has a diameter of 19 feet. If water
pogonyaev

We know that the volume of a sphere is:

V

=

4

3

π

r

3

where

r

=

10

2

=

5

ft

is the radius;

we need half of this, so we use:

V

2

=

2

3

π

r

3

=

261.8

ft

3

giving a total weight of water of:

W

=

261.8

⋅

62.4

=

16

,

336

pounds

6 0
3 years ago
Read 2 more answers
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