$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{a^{-4}}{a^{-6}}\implies a^{-4}\cdot a^6\implies a^{-4+6}\implies a^2$

7 0

2 years ago

PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS

gayaneshka [121]

Answer:

( 1, -2)

step-by-step explanation:

original coordinates of C: (4, -2)

if reflected over y-axis: use the formula: (x,y) → (-x,y)

new coordinates: (-4, -2)

then if translated 5 units horizontally, there will be change in x axis:

new coordinates: (-4+5, -2) → ( 1, -2)

7 0

1 year ago

36 POINTS HURRYYYYYY What procedure can be used to solve the equation 540 = StartFraction a Over 11 EndFraction, and what is the

mina [271]

Answer:

Divide StartFraction a Over 11 EndFraction by 11; the solution is 540.

Step-by-step explanation:

6 0

3 years ago

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