Answer:It all depends on who the reader is likely to be and the information they’ll want.
Explanation:
Newspaper 1: Company wins contract
Newspaper 2: Previous company loses contract (equally true)
Newspaper 3, say a student paper in the local town: Prospects for new jobs open up as company wins contract.
The well-designed standard architecture for security features in computer networking is defined by the OSI Security Architecture.
The OSI architecture is widely accepted because it establishes the process for ensuring safety in an organization. In a live attack, the victim is made aware of it. The victim of a passive attack is not made aware of the attack. System resources can be modified during an active attack. System resources are not changing while under passive attack. Monitoring a system is the focus of passive assaults, which do not require changing any data on the target system. On the system under attack, active threats will alter data.
Learn more about system here-
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Answer:
Machine Language.
Explanation:
The most basic language that is used by computers so that they can control the operation of the on/off switches in the circuitry is Machine language.
Machine Language is a low level language is a collection of binary digits or bits that is understood by the computers.Computers are capable of understanding only machine language.
Answer:
public class MagicSquare {
public static void main(String[] args) {
int[][] square = {
{ 8, 11, 14, 1},
{13, 2, 7,12},
{ 3, 16, 9, 6},
{10, 5, 4, 15}
};
System.out.printf("The square %s a magic square. %n",
(isMagicSquare(square) ? "is" : "is not"));
}
public static boolean isMagicSquare(int[][] square) {
if(square.length != square[0].length) {
return false;
}
int sum = 0;
for(int i = 0; i < square[0].length; ++i) {
sum += square[0][i];
}
int d1 = 0, d2 = 0;
for(int i = 0; i < square.length; ++i) {
int row_sum = 0;
int col_sum = 0;
for(int j = 0; j < square[0].length; ++j) {
if(i == j) {
d1 += square[i][j];
}
if(j == square.length-i-1) {
d2 += square[i][j];
}
row_sum += square[i][j];
col_sum += square[j][i];
}
if(row_sum != sum || col_sum != sum) {
return false;
}
}
return d1 == sum && d2 == sum;
}
}
Answer:
1) press the enter key
2) start typing the new paragraph
Explanation:
did it on edg
